anonymous
  • anonymous
help area of shaded region
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
geerky42
  • geerky42
Can you find area of semicircle?
geerky42
  • geerky42
Semicircle is just half the circle. So it's like finding area of circle, but THEN you divide it by 2.

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anonymous
  • anonymous
yes that 4.71cm2
anonymous
  • anonymous
@geerky42
anonymous
  • anonymous
was that right @geerky42 ?
anonymous
  • anonymous
@Michele_Laino
geerky42
  • geerky42
No.
geerky42
  • geerky42
Area of circle is \(A = \pi r^2\) So to find area of semicircle, you just use this formula then divide by 2.
anonymous
  • anonymous
but you said semi circle so wouldn't it be A=1/2pi r
geerky42
  • geerky42
My point is, to find semicircle, you just find area of circle, then divide by 2. Get it? Also it's \(\pi r^2\), not just \(\pi r\).
geerky42
  • geerky42
So area of semicircle is \(\dfrac{\pi r^2}{2}\)
anonymous
  • anonymous
@geerky42 so 9.42cm2/2=4.71cm2
geerky42
  • geerky42
Radius is 3, so you have \(\dfrac{\pi(3)^2}{2} = \dfrac{9\pi}{2}\approx 14.137\)
geerky42
  • geerky42
Just remember that \(\pi\approx3.14\)
anonymous
  • anonymous
yes you told me that, thats how remember what pi is but how did you get the 9pi over 2
geerky42
  • geerky42
\(3^2 = 9\)
geerky42
  • geerky42
you divide 2 because semicircle
geerky42
  • geerky42
Is that clear?
anonymous
  • anonymous
yes kinda
anonymous
  • anonymous
thank you though @geerky42
geerky42
  • geerky42
Well, we are not done
geerky42
  • geerky42
we got area of semicircle. Now we need to subtract that by area of triangle
geerky42
  • geerky42
(Area of semicircle) - (Area of triangle) Right?
anonymous
  • anonymous
yea
geerky42
  • geerky42
Ok. Area of triangle is \(\dfrac{1}{2}bh\) Do you know base and height here?
anonymous
  • anonymous
but we don't have the area of the triangle so we need to solve for the triangle
geerky42
  • geerky42
Right.
anonymous
  • anonymous
so 3 would be our height
anonymous
  • anonymous
so how would you find the base given only the height
geerky42
  • geerky42
We don't really have to use height to find base. Triangle and semicircle share same base, right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
do the MAGIC! drawing thing geerky
geerky42
  • geerky42
We know that radius of semicircle is 3, so what is diameter?
anonymous
  • anonymous
:D
anonymous
  • anonymous
hahaaaa @camacho01erick that was the best response
geerky42
  • geerky42
lol. though I don't see the need to drawing something here lol.
anonymous
  • anonymous
1.5
geerky42
  • geerky42
maybe I will do magic thing once asker solve something like gif of victory lol.
geerky42
  • geerky42
@Mromanos96 No \(d = 2r\), right?
anonymous
  • anonymous
k
anonymous
  • anonymous
yes
anonymous
  • anonymous
6
geerky42
  • geerky42
|dw:1433962650107:dw|
anonymous
  • anonymous
:0
geerky42
  • geerky42
Yeah so diameter is 6. Therefore base of triangle is 6. MAke sense so far?
anonymous
  • anonymous
yes so next we have 1/2 6*3
geerky42
  • geerky42
|dw:1433962764011:dw|
geerky42
  • geerky42
Sorry yesh that's correct.
anonymous
  • anonymous
lol funny ones
geerky42
  • geerky42
just laughing at ":0"
anonymous
  • anonymous
so thats 3/64 @geerky42 great gif btw
anonymous
  • anonymous
that kinda scares me
anonymous
  • anonymous
@camacho01erick it kinda does if you look at it for a little
anonymous
  • anonymous
ikr
geerky42
  • geerky42
|dw:1433962900186:dw|
anonymous
  • anonymous
how do you do that :D
anonymous
  • anonymous
:0 my favorite show man
anonymous
  • anonymous
@camacho01erick he's a wizard
anonymous
  • anonymous
fa fa fabulas
geerky42
  • geerky42
Anyway, no I got 9 for area of triangle
geerky42
  • geerky42
\(\dfrac{1}{2}*3*6 = 3*3 = 9\)
geerky42
  • geerky42
Right? @Mromanos96
anonymous
  • anonymous
how didi you do the gif @geerky42
anonymous
  • anonymous
ah how did you get that the only other one i got is a decimal
geerky42
  • geerky42
For area of triangle?
geerky42
  • geerky42
Did you use calculator?
geerky42
  • geerky42
I guess I need to make tutorial @camacho01erick in LaTeX section. I will tag you someday, I promise.
anonymous
  • anonymous
kk
anonymous
  • anonymous
yea
anonymous
  • anonymous
good thing i fanned you @geerky42
geerky42
  • geerky42
Well, put that in calculator 1/2 * 3 * 6
geerky42
  • geerky42
You should get 9, right?
geerky42
  • geerky42
lol @camacho01erick
anonymous
  • anonymous
yup
anonymous
  • anonymous
|dw:1433963336155:dw|
anonymous
  • anonymous
so 9cm^2
geerky42
  • geerky42
OK. Now do final thing; (Area of semicircle) - (Area of triangle)
geerky42
  • geerky42
We have \(14.137 - 9\)
anonymous
  • anonymous
we are /\tlas we will follow and we will not forget and will not forgive
anonymous
  • anonymous
5.137
geerky42
  • geerky42
Yep. Sorry first area should be \(14.13\) since we have to use \(3.14\) for pi. But anyways your final answer is \(\boxed{5.13~\text{cm}^2}\)
geerky42
  • geerky42
Is that clear so far?
anonymous
  • anonymous
yes crystal
geerky42
  • geerky42
ok good.
anonymous
  • anonymous
@geerky42 one last question
geerky42
  • geerky42
https://www.mathsisfun.com/data/relative-frequency.html
geerky42
  • geerky42
And here, voting registration status is irrelevant.
geerky42
  • geerky42
So we just need to find how many adult prefer newspapers Then divide it by 252 (total)
geerky42
  • geerky42
Follow me so far?
anonymous
  • anonymous
yes
geerky42
  • geerky42
OK. how nay adults prefer newspaper?
geerky42
  • geerky42
how many*
anonymous
  • anonymous
46+24=70
anonymous
  • anonymous
hi
anonymous
  • anonymous
70 /252= 0.2
geerky42
  • geerky42
Correct. So relative frequency is \(\dfrac{70}{252}=?\)
geerky42
  • geerky42
yeah but close. question said at least two decimal places.
geerky42
  • geerky42
So we have 70/252 = 2.777777777... So round that to .28
anonymous
  • anonymous
0.27
geerky42
  • geerky42
That's your answer.
anonymous
  • anonymous
so it .28 not 0.28
anonymous
  • anonymous
|dw:1433964202516:dw|
geerky42
  • geerky42
Well it is closer to .28 than .27
geerky42
  • geerky42
0.28 and .28 are same
anonymous
  • anonymous
true
anonymous
  • anonymous
so really .28 or 0.28 because ales is very specific on it
geerky42
  • geerky42
I would go with 0.28
anonymous
  • anonymous
ok @geerky42 last one promise
geerky42
  • geerky42
|dw:1433964384649:dw|
geerky42
  • geerky42
sorry no need to use graph
geerky42
  • geerky42
But here, "input" is time spending in texting. Here, you have x = 4 So plug that into best fit line \(y = -0.73x+8.53\)
anonymous
  • anonymous
5.61
geerky42
  • geerky42
\[y = -0.73(\bf\color{blue}4)+8.53\]
geerky42
  • geerky42
yeah 5.61 is your answer.
anonymous
  • anonymous
anonymous
  • anonymous
alright man thanks so much @geerky42
geerky42
  • geerky42
No problem
anonymous
  • anonymous
and um how do you do those gifs lol
geerky42
  • geerky42
|dw:1433964611059:dw|
geerky42
  • geerky42
I will make tutorial of it by tonight. Check tomorrow.
anonymous
  • anonymous
but how on drawing????
geerky42
  • geerky42
I will make tutorial later, I promise. Check tomorrow.
geerky42
  • geerky42
It's little complicated.
anonymous
  • anonymous
ok message us tommorow
geerky42
  • geerky42
I will tag. You want message anyway?
anonymous
  • anonymous
sure
geerky42
  • geerky42
What about you? Or nah? @Mromanos96
anonymous
  • anonymous
yeah tag me also
geerky42
  • geerky42
ok I will tag both you
anonymous
  • anonymous
geerky is a new moderator lol
geerky42
  • geerky42
I wish lol.
anonymous
  • anonymous
but how can you be a moderator anyways
anonymous
  • anonymous
a beginner have done it
geerky42
  • geerky42
You got to apply somewhere... I don't know because I was planning on doing that anyway lol.
anonymous
  • anonymous
|dw:1433964783733:dw|
geerky42
  • geerky42
You can ask that on OpenStudy feedback.
anonymous
  • anonymous
lol he'd be the number one
geerky42
  • geerky42
I wasn't planning*
anonymous
  • anonymous
i copyed yours lol
geerky42
  • geerky42
I can see that ;)
anonymous
  • anonymous
lol
anonymous
  • anonymous
we are /\tlas we will follow we will not forget and we will not forgive
anonymous
  • anonymous
bye

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