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anonymous
 one year ago
In a lab experiment, a 0.6g peanut is burned beneath 60 g of water. Heat from the burning peanut raises the water temperature from 22⁰C to 50⁰C in 3.0 minutes. If the heat transfer is 41% efficient, how many Calories of heat did the peanut release while burning? Show all calculations leading to an answer.
anonymous
 one year ago
In a lab experiment, a 0.6g peanut is burned beneath 60 g of water. Heat from the burning peanut raises the water temperature from 22⁰C to 50⁰C in 3.0 minutes. If the heat transfer is 41% efficient, how many Calories of heat did the peanut release while burning? Show all calculations leading to an answer.

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Sachintha
 one year ago
Best ResponseYou've already chosen the best response.0I think this is more probably suitable for physics section.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres a physics section?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is definitly physics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can use the specific heat equation, I'm just not sure where the time comes in

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I really don't think it comes into play because it's asking about energy, not power. It just might be a number thrown in there.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im gonna re enter this in physics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because you don't need the mass of the peanut either

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what do you think i should do @peachpi

Sachintha
 one year ago
Best ResponseYou've already chosen the best response.0I hope this would be answered in the physics section. Good luck! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no one is online to help apparently @Sachintha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the amount of heat needed to raise the temperature of the water \[Q = mC(T _{f}T _{i})\] \[Q = (60~g)(1~cal/g°C)(50°C22°C)\] \[Q = 1,680~cal\] This is 41% of the heat released by the peanut. \[0.41x=1680\] \[x=4,098~cal\]

Sachintha
 one year ago
Best ResponseYou've already chosen the best response.0Exactly what I said. Anyway are you sure about the answer? @peachpi I didn't knew the specific heat capacity of water in calories (knew only in joules) since I didn't know the definition of a calorie. :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes because if you work it with C in J/g°C then convert to calories at the end you get the same answer
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