anonymous
  • anonymous
In a lab experiment, a 0.6-g peanut is burned beneath 60 g of water. Heat from the burning peanut raises the water temperature from 22⁰C to 50⁰C in 3.0 minutes. If the heat transfer is 41% efficient, how many Calories of heat did the peanut release while burning? Show all calculations leading to an answer.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Luigi0210 can you please help me
Sachintha
  • Sachintha
@ganeshie8 @Michele_Laino
Sachintha
  • Sachintha
Does question mention what the answer we are supposed to get?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
no :/ iv posted everything i have on it
anonymous
  • anonymous
luigi you know anything about this
Sachintha
  • Sachintha
I think this can be solved calculating the energy gained by water and putting it into energy efficiency equation. P.S. I am really not good at physics. So I am not sure about it. :(
Sachintha
  • Sachintha
@Luigi0210 Any idea?
Luigi0210
  • Luigi0210
Maybe @Abhisar or @annas
anonymous
  • anonymous
noone can help me apparently lol
anonymous
  • anonymous
hey luigi i have a different question you could possibly help me with

Looking for something else?

Not the answer you are looking for? Search for more explanations.