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anonymous

  • one year ago

A circular picture is 8 inches in diameter. Part A What is the area of the picture in square inches? A. 4π square inches B. 8π square inches C. 16π square inches D. 32π square inches Part B A frame that is 2 inches wide surrounds the picture. What is the total area of the picture and the frame in square inches? A. 4π square inches B. 12π square inches C. 36π square inches D. 40π square inches

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  1. anonymous
    • one year ago
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    @Nnesha

  2. anonymous
    • one year ago
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    @Abhisar

  3. anonymous
    • one year ago
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    @Nnesha

  4. Abhisar
    • one year ago
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    For Part A Area of a square = \(\sf \pi \times r^2\) Where, r = radius = diameter/2

  5. Abhisar
    • one year ago
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    Can u do it now?

  6. anonymous
    • one year ago
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    umm i still dont get it :(

  7. Abhisar
    • one year ago
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    Which part?

  8. anonymous
    • one year ago
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    for part A, a?

  9. anonymous
    • one year ago
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    ??

  10. Abhisar
    • one year ago
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    \(\huge \checkmark\)

  11. anonymous
    • one year ago
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    are you sure?

  12. Abhisar
    • one year ago
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    Yes, are you?

  13. anonymous
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    now lets do part b

  15. Abhisar
    • one year ago
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    No wait, no it's wrong.

  16. Abhisar
    • one year ago
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    :(

  17. Abhisar
    • one year ago
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    One silly mistake.

  18. anonymous
    • one year ago
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    what is it

  19. Abhisar
    • one year ago
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    Diameter is given 8, so radius will be 8/2 = 4. Correct?

  20. anonymous
    • one year ago
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    yes

  21. Abhisar
    • one year ago
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    Now, putting this value of radius in the formula I just told you we get area = \(\sf \pi \times 4^2\) = ?

  22. anonymous
    • one year ago
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    whats the symbol in the beginning mean?

  23. Abhisar
    • one year ago
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    It's called as "pi" and its value = 3.14. So if it is written \(\sf 16 \pi\), it actually means 16 \(\sf \times ~\pi\) or if you want to simplify it more it means 3.14 \(\sf \times\) 16

  24. anonymous
    • one year ago
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    ok

  25. Abhisar
    • one year ago
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    Moving on to the question, the correct answer for part A is?

  26. anonymous
    • one year ago
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    i got 16

  27. Abhisar
    • one year ago
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    Yes, \(\sf 16 \pi\) square inch to be more precise. Don't forget the "pi" !

  28. anonymous
    • one year ago
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    ok thank you so much... dont leave because i will be tagging you again!! :)

  29. Abhisar
    • one year ago
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    I m not leaving, so shall we move to part B?

  30. anonymous
    • one year ago
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    yes

  31. Abhisar
    • one year ago
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    Any idea?

  32. anonymous
    • one year ago
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    uhh no

  33. anonymous
    • one year ago
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    @Abhisar

  34. Abhisar
    • one year ago
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    So, any idea about Part B?

  35. anonymous
    • one year ago
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    whats the equation, ill solve it

  36. Abhisar
    • one year ago
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    |dw:1433965184199:dw|

  37. Abhisar
    • one year ago
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    This is ur square frame which is 2 inch wide. Area of a square = \(\sf side^2\)

  38. anonymous
    • one year ago
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    0k @Abhisar

  39. Abhisar
    • one year ago
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    So the answer should be?

  40. anonymous
    • one year ago
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    b

  41. anonymous
    • one year ago
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    8

  42. Abhisar
    • one year ago
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    oops..

  43. Abhisar
    • one year ago
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    we did the part B wrong..

  44. Abhisar
    • one year ago
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    |dw:1433965519276:dw|

  45. anonymous
    • one year ago
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    whats the equation

  46. Abhisar
    • one year ago
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    The frame is also circular and surrounds the circular picture. It says that the frame is 2 inches wide. Thus the radius of frame would be 4+2= 6 inch.

  47. Abhisar
    • one year ago
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    Now, find the area by same equation u used before.

  48. anonymous
    • one year ago
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    i got 36

  49. Abhisar
    • one year ago
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    Are you missing something? Only 36?

  50. anonymous
    • one year ago
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    and 36 pie

  51. Abhisar
    • one year ago
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    Correct 36\(\sf \pi\) square inch. Don't miss the pi if u want a apple pie (-:

  52. Abhisar
    • one year ago
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    It's Pi not pie. Pie is the one u eat.

  53. anonymous
    • one year ago
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    lol thanks :)

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