When 4.5 mol Al react with 11.5 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2 Al + 6 HCl → 2 AlCl3 + 3 H2

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When 4.5 mol Al react with 11.5 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Al is the limiting reactant, 4.5 mol H2 can be formed HCl is the limiting reactant, 3.8 mol H2 can be formed Al is the limiting reactant, 6.8 mol H2 can be formed HCl is the limiting reactant, 5.8 mol H2 can be formed

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I think it's B.

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