- anonymous

Rewrite the rational exponent as a radical.
5 to the 3 over 4 power, to the 2 over 3 power
Answer Choices:
A) the cube root of 5 squared
B) the twelfth root of 5
C) the square root of 5
D)the cube root of 5 the fourth power
I think it's A but im not sure, someone please help?

- jamiebookeater

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- Nnesha

\[\huge\rm (5^\frac{ 5 }{ 4 })^\frac{ 2 }{ 3 }\] like this ?

- anonymous

@Nnesha Yes.

- Nnesha

well can you take a screenshot i think i typed it wrong

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## More answers

- anonymous

##### 1 Attachment

- anonymous

@Nnesha did you get it?

- Nnesha

weird question ....
why do you think it's A ?

- anonymous

@Nnesha When I worked out the problem I some how ended up with A

- Nnesha

well i didn't get A i got*NONE*
ORR i'm not paying attention

- Nnesha

@freckles ???

- Nnesha

you have to apply exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\]
multiply exponents and then reduce the fraction

- anonymous

@Nnesha I did so, I did it 4 more times and got different answers each time. I have no idea anymore.

- freckles

hey

- freckles

hey @Nnesha he said to ...to the 3/4 power...
but then he said yes when you put 5/4 instead...

- freckles

\[(5^{\frac{3}{4})\frac{2}{3}} =5^{\frac{3}{4} \cdot \frac{2}{3}}\]
first look at the fraction multiplication action going on there:
\[\frac{3}{4} \cdot \frac{2}{3}\]
can you simplify that?

- freckles

basically you need to simplify 3/3 and 2/4

- Nnesha

*facepalm* it's 3/4 >.<

- anonymous

wow my mistake guys :/ im so sorry

- Nnesha

my bad..
thanks freckles

- freckles

does @06292014 still need help?
if so have you done the multiplication I asked about?

- anonymous

@freckles I got 1/2

- freckles

cool so you have 5^(1/2)

- freckles

which is the same as square root of 5

- anonymous

##### 1 Attachment

- freckles

look at the exponents
do top exponent - bottom exponent

- Nnesha

i can't zoomin in this pdf http://assets.openstudy.com/updates/attachments/557890d9e4b0636b8cc2974f-06292014-1433965330041-cuserspattydocumentsscreenshot.pdf
and people like me barely can see this^
;P

- Nnesha

and write these down 'n ur notes \[\huge\rm x^m \times x^n = x^{m+n}\]\[\large\rm (x^m)^n =x^{m \times n}\]\[\large\rm \frac{ x^m }{ x^n }= x^{m-n}\]

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