A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
last day of school need help please will medal
What is the value of x? Round your answer to the nearest tenth if necessary.
http://static.k12.com/calms_media/media/1577500_1578000/1577934/1/d63edcbef5c7e0eba3c6f1108512f46d670e145a/MS_IMC150120130102.jpg
anonymous
 one year ago
last day of school need help please will medal What is the value of x? Round your answer to the nearest tenth if necessary. http://static.k12.com/calms_media/media/1577500_1578000/1577934/1/d63edcbef5c7e0eba3c6f1108512f46d670e145a/MS_IMC150120130102.jpg

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Compassionate @KyanTheDoodle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its ur last day lucky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah its cause im home schooled

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0same i still got a while tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to finish today

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0this is a right triangle yes?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0then use pythagoras\[a^2+b^2=c^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so 5^2 is 25 and 8^2 is 64 right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x = \sqrt{5^{2}+8^{2}}\] x = sqrt{25+64} x = sqrt{89} x = 9.43
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.