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anonymous
 one year ago
Which combination of integers can be used to generate the Pythagorean triple 7,24,25
anonymous
 one year ago
Which combination of integers can be used to generate the Pythagorean triple 7,24,25

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.3the question is a little unclear, but maybe it is this: all triples can be found by taking whole number \(m,n\) and computing \[m^2n^2, 2mn, m^2+n^2\] is that what you have to find, \(m\) and \(\)?

Elsa213
 one year ago
Best ResponseYou've already chosen the best response.2Welcome to Openstudy! :D

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3@Elsa213 thanks dear, welcome to you as well!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its apex so the answers would be like A.x=4,y=3 B.X=1, y+3 C.x=3,y=2 D.x=2 y=2

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3what does "it is apex" mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and thanks for the warm welcome and its an online class

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3ok it looks like they used \(x\) and \(y\) whereas i used \(m\) and \(n\) but it is the same thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what would be the answer?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3you have \[x^2y^2=7\] that is the same as \[(xy)(x+y)=7\] there is only one way to factor \(7\) as \(1\times 7\) so \[xy=1\\ x+y=7\] and using that you can solve for \(x\) and \(y\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i basically plug in and solve

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3you can solve that in your head: two numbers that add to 7 and are one apart

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3ooh i see A is \(x=4,y=3\) yes, that is right
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