anonymous
  • anonymous
last question What is the value of x? Round your answer to the nearest tenth if necessary. http://static.k12.com/calms_media/media/1577500_1578000/1577938/1/c840947ced6d410d5858579e26880ce72f28d4db/MS_IMC-150120-130106.jpg
Mathematics
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anonymous
  • anonymous
last question What is the value of x? Round your answer to the nearest tenth if necessary. http://static.k12.com/calms_media/media/1577500_1578000/1577938/1/c840947ced6d410d5858579e26880ce72f28d4db/MS_IMC-150120-130106.jpg
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Godlovesme
  • Godlovesme
use the Pythagorean theorem \[a^2 + b^2 = c^2\]
anonymous
  • anonymous
so 6^2 + 17^2=c^2

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Godlovesme
  • Godlovesme
no 17 is the c because it's the hypotenuse so it would be \[6^2 + x^2 = 17^2\]
anonymous
  • anonymous
ok
anonymous
  • anonymous
and 6^2 is 36 right
Godlovesme
  • Godlovesme
yes :)
anonymous
  • anonymous
and 17^2 is 289
anonymous
  • anonymous
36+x^2=289
Godlovesme
  • Godlovesme
you're doing great! :)
anonymous
  • anonymous
this is the part when i dont know what to do now
anonymous
  • anonymous
would i subtract 36 from 289
Godlovesme
  • Godlovesme
ok now subtract 36 from both sides
anonymous
  • anonymous
36-36+x^2=289-36
anonymous
  • anonymous
x^2=253
Godlovesme
  • Godlovesme
good job! now take the square root of 253
anonymous
  • anonymous
15.90
Godlovesme
  • Godlovesme
yep! c:
anonymous
  • anonymous
thank you
Godlovesme
  • Godlovesme
anytime :)

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