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mathmath333
 one year ago
solve for x.
mathmath333
 one year ago
solve for x.

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2\(\large \color{black}{\begin{align} x3+x+5=7,\ \ x\in \mathbb{R}\hspace{.33em}\\~\\ \end{align}}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2algebra absolute value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x∈R i have never seen this before

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2that means x is an element of set of real numbers

freckles
 one year ago
Best ResponseYou've already chosen the best response.3Break into cases. we have x3=0 if x=3 and we have x+5=0 if x=5 dw:1433970138088:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.3So let's look at case 1 x<5 if x<5 then x+3=(x3) and x+5=(x+5) so you look at solving (x3)(x+5)=7

freckles
 one year ago
Best ResponseYou've already chosen the best response.3And case 2 5<x<3 if we have this case then x+3=(x3) and x+5=x+5 so you look at solving (x3)+(x+5)=7

freckles
 one year ago
Best ResponseYou've already chosen the best response.3I will let you type out case 3 but anyways we need to solve these equations in the two cases I have already mentioned

freckles
 one year ago
Best ResponseYou've already chosen the best response.3look and I made a typeo everywhere I have x+3 I meant to write x3

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2\(x=\pm x\) so we should havr four cases like this \(\large \color{black}{\begin{align} &x3+x+5=7,\ \ x\in \mathbb{R}\hspace{.33em}\\~\\ &\implies x3+x+5=7,\hspace{.33em}\\~\\ &\implies x3(x+5)=7,\hspace{.33em}\\~\\ &\implies (x3)+x+5=7,\ \ x\in \mathbb{R}\hspace{.33em}\\~\\ &\implies (x3)(x+5)=7,\hspace{.33em}\\~\\ \end{align}}\) can this be solved like this

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.1We have to break in 3 cases. 1) x<5 2)5<x<3 <,> with equal to sign 3)x>3

freckles
 one year ago
Best ResponseYou've already chosen the best response.3I guess you an do the cases like that just make sure you check the solutions by pluggin into original because you only need to look at really So let's look at case 1 x<5 if x<5 then x3=(x3) and x+5=(x+5) so you look at solving (x3)(x+5)=7 And case 2 5<x<3 if we have this case then x3=(x3) and x+5=x+5 so you look at solving (x3)+(x+5)=7 And lastly case 3 x>3 which we have both x3=x3 and x+5=x+5 (x3)+(x+5)=7 so of the cases you wrote out you only need to look at your case 1,3,4 \[\large \color{black}{\begin{align} &x3+x+5=7,\ \ x\in \mathbb{R}\hspace{.33em}\\~\\ &\implies x3+x+5=7,\hspace{.33em}\\~\\ &\cancel{\implies x3(x+5)=7,\hspace{.33em}}\\~\\ &\implies (x3)+x+5=7,\ \ x\in \mathbb{R}\hspace{.33em}\\~\\ &\implies (x3)(x+5)=7,\hspace{.33em}\\~\\ \end{align}}\]

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.1In first case both mode . open with minus sign. In second x3 only open with minus sign. In third case both mode. Open with plus sign now solve the 3 eq.'s

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.1We have to break in 3 cases. 1) x<5 2)5<x<3 <,> with equal to sign 3)x>3

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.2got 9/2 ,5/2 for case 1 and 3

freckles
 one year ago
Best ResponseYou've already chosen the best response.3So let's look at case 1 x<5 if x<5 then x3=(x3) and x+5=(x+5) so you look at solving (x3)(x+5)=7 And case 2 5<x<3 if we have this case then x3=(x3) and x+5=x+5 so you look at solving (x3)+(x+5)=7 And lastly case 3 x>3 which we have both x3=x3 and x+5=x+5 (x3)+(x+5)=7 Case 1) you got x=9/2 but 9/2<5 is false so x=9/2 is not a solution Case 3) you got x=5/2 but 5/2>3 is not true so x=5/2 is not a solution so there are no solutions to x3+x+5=7

freckles
 one year ago
Best ResponseYou've already chosen the best response.3also if you try to graph y=x3+x+5 and y=7 you will see no intersection

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1"so there are no solutions to x3+x+5=7" second that
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