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anonymous

  • one year ago

A rectangular barge 6 m long and 3 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand? Show all calculations leading to an answer.

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  1. anonymous
    • one year ago
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    Let sink depth=d volume of displaced water ...V = 3x 6 x d V = 18 d .... is its weight..So, 18000d kg equals 600 kg.... so d= 0.033 metres @quick24

  2. anonymous
    • one year ago
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    @aryandecoolest hey are you still online

  3. anonymous
    • one year ago
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    yeah

  4. anonymous
    • one year ago
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    how did you change 18d to 18000 d?

  5. anonymous
    • one year ago
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    volume is in m^3 and density of water is 1000 kg/m^3

  6. anonymous
    • one year ago
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    you can do it other way round. The displaced water occupies about 600/1000=.6m³ .6m³/18m². Both gives you same answer :) hope it's clear

  7. anonymous
    • one year ago
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    ok so 600kg is the space the sand occupies in waters place and v=3x6xd because d=sink depth and we know 18d=v and v=600kg

  8. anonymous
    • one year ago
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    so therefor 600kg=18d

  9. anonymous
    • one year ago
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    you know buoyancy. Buoyancy,h=mg/pglw, l,w = length and width so h= 6000kg *9.8 m/s^2/1000kg/m^3*9.8m/s^2*6m*3m

  10. anonymous
    • one year ago
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    h=5880 kg *m/s^2/176400 kg/s^2=1/30m Hope it's quite clear.

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