anonymous
  • anonymous
A rectangular barge 6 m long and 3 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand? Show all calculations leading to an answer.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Let sink depth=d volume of displaced water ...V = 3x 6 x d V = 18 d .... is its weight..So, 18000d kg equals 600 kg.... so d= 0.033 metres @quick24
anonymous
  • anonymous
@aryandecoolest hey are you still online
anonymous
  • anonymous
yeah

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anonymous
  • anonymous
how did you change 18d to 18000 d?
anonymous
  • anonymous
volume is in m^3 and density of water is 1000 kg/m^3
anonymous
  • anonymous
you can do it other way round. The displaced water occupies about 600/1000=.6m³ .6m³/18m². Both gives you same answer :) hope it's clear
anonymous
  • anonymous
ok so 600kg is the space the sand occupies in waters place and v=3x6xd because d=sink depth and we know 18d=v and v=600kg
anonymous
  • anonymous
so therefor 600kg=18d
anonymous
  • anonymous
you know buoyancy. Buoyancy,h=mg/pglw, l,w = length and width so h= 6000kg *9.8 m/s^2/1000kg/m^3*9.8m/s^2*6m*3m
anonymous
  • anonymous
h=5880 kg *m/s^2/176400 kg/s^2=1/30m Hope it's quite clear.

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