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i need help
do you know what the form of the equation y=mx+b means?
no i do not
so - you are studying straight line equations have you seen the equation y=mx + b before?
yes i have but i honestly dont really get it
do you know what the slope of a straight line is?
are you talking bout the y1,y2/x1,x2
yes - that is correct (but it is y1-y2/x1-x2) you can use the 2 points you are given to work out the slope from that equation
fill in the numbers - from the points: x1= x2= x1-x2= y1= y2= y1-y2= y1-y2/x1-x2 =
ok give me a min im going to do it
my answer is 0.5
that is good - correct now in the equation y=mx +b the slope is the value m so you can start to make the equation y= 0.5x +b OK so far?
so should i make -12 or -8 my y intercept
so - don't rush ahead... the equation is y=0.5x+b and you know that the point (6,-8) is on th eline so you can fill in some numbers: -8 = 0.5(6) +b (that is th esame equation but we pput the values from one of the known points in OK? so now you can work out b from that equation...
ok can you tell me how to get b
I SHOWED YOU HOW TO PUT TH EVALUES OF ONE OF TH EPOINTS INTO THE EQUATION (oops) to give you this: -8 = 0.5(6) +b so solve that to get a number for b
what is 0.5(6) i.e. 0.5 times 6??
so the equation I wrote is -8 = 3 +b so what is b?
well done - that is correct so in the general equation y=mx + b you worked out that m = 0.5 you worked out that b = -11 so the equation is y=0.5x -11 you can check that by looking at the point (-2,-12) is the equation true for that point?
OK - so you did it!
thank you soo much