I cannot figure out how to calculate the area of this irregular figure and I could use some help. Thanks!

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I cannot figure out how to calculate the area of this irregular figure and I could use some help. Thanks!

Mathematics
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i think i would divide it into two trapezoids. one on top and other on bottom
Any idea how I can figure out the lengths of each side? I'm fairly stumped on that

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I agree. Use a horizontal line to divide the figure into two trapezoids. You need to make a few assumptions, if you were not told this info specifically. The bottom right angle must be a right angle. The two side endpoints in the middle of the right and left sides must be at the same height.
|dw:1433972764485:dw|
How do we know that the two points coming off the right angle are the same height?
|dw:1433972877965:dw| you're two trapezoids
|dw:1433972904320:dw|
|dw:1433972929542:dw|
260-15- is 110, so the height of the top trpaezoid is 110. and that means the bottom ones hjeight must be 150.
yup
|dw:1433972798403:dw|
Then we get 110*195?
for the top trapezoid
@ganeshie8 I don't understand your question. The figure clearly shows that the maximum width of the polygon is 265 ft. How can you move the vertex on the left and make it narrower than 265 ft?
^I agree. and to find area of trapezoid (sum of bases/2) x height so the top would be [(125+265)/2]x 110
THis is what I am putting down for the top, am I correct? We know the top is 110 high (260-150), and then we do A=110*((265+125)/2 which adds up to 21450 square feet in the top trapezoid.
Ignore the missing parenthesis
yes. i got that for the top one too
Ahh so it doesn't matter where the left most vertex moves on the vertical line |dw:1433973606686:dw|
Awesome. SO now all we have left is the bottom?
(for area)
ANd we know the hegiht is 15, the base is 15, and the lid is 265
Right?
*150 instead of 15
Read my comment way above. We need to make two assumptions for this problem to be solvable with the info we are given.
Ya, I have to assume 150 for the sides
|dw:1433973761953:dw|
yes. that is true. now plug those numbers into the formula to find area. also if we dont assume these things, i dont think we have enough info
`The two side endpoints in the middle of the right and left sides must be at the same height.` this assumption is also not required right ?
If you do not make that assumption, you may not have two trapezoids.
doesn't matter, area wont change
We also need to assume that the top side and the bottom side are parallel to each other and parallel to the mid segment.
The area won;t change, but how will you calculate it if we do not deal with trapezoids?
that is a different problem haha
@ganeshie8, are you saying I have the wrong question?
@ganeshie8 Right. BTW, how do you copy a figure into the draw tool, and how do you edit it in color like you did above?
nope, im still trying to convince myself that the actuall question is valid as it stands
the bottom looks right. now just add the two areas together and you have solved your problem based on a lot of assumptions then
Whether or not the question is valid, I gotta write in something. I have 2 days to go before the simester ends and everything closes up, and since I got hit by a car on the 12th last month, I am behind around a week at this point.
To solve this, we cut the top into a trapezoid and the bottom into a trapezoid. We know the top is 110 high (260-150), and then we do A=110*((265+125)/2) which adds up to 21450 square feet in the top trapezoid. Bottom trapezoid has a base of 150, a height of 150, and a lid with a length of 265. 31125=150*((265+150)/2) Is this correct? Assuming we made all the agreed on assumptions that have to be done.
I think I have an answer, can I beg one of you to check it?
yea. that looks right. but i dont know why you call it a lid, instead of just the other base. and dont forget your last step, to add both the areas
Alright, thanks man.
I really do appreciate all your guys help. I was lost on this one.
I have another account if one of you guys wants another medal
Never do that. Medal the person that helps you most.
Youall helped me a ton. I gave the medal to Nikato, but thank you all.
You're welcome.
Should I close it, or did you guys want to continue talking?
It is okay to close as soon as you're done because you can't open a new question w/o closing the present q
Alright.

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