anonymous
  • anonymous
I cannot figure out how to calculate the area of this irregular figure and I could use some help. Thanks!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
nikato
  • nikato
i think i would divide it into two trapezoids. one on top and other on bottom
anonymous
  • anonymous
Any idea how I can figure out the lengths of each side? I'm fairly stumped on that

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More answers

mathstudent55
  • mathstudent55
I agree. Use a horizontal line to divide the figure into two trapezoids. You need to make a few assumptions, if you were not told this info specifically. The bottom right angle must be a right angle. The two side endpoints in the middle of the right and left sides must be at the same height.
nikato
  • nikato
|dw:1433972764485:dw|
anonymous
  • anonymous
How do we know that the two points coming off the right angle are the same height?
nikato
  • nikato
|dw:1433972877965:dw| you're two trapezoids
nikato
  • nikato
|dw:1433972904320:dw|
nikato
  • nikato
|dw:1433972929542:dw|
anonymous
  • anonymous
260-15- is 110, so the height of the top trpaezoid is 110. and that means the bottom ones hjeight must be 150.
nikato
  • nikato
yup
ganeshie8
  • ganeshie8
|dw:1433972798403:dw|
anonymous
  • anonymous
Then we get 110*195?
anonymous
  • anonymous
for the top trapezoid
mathstudent55
  • mathstudent55
@ganeshie8 I don't understand your question. The figure clearly shows that the maximum width of the polygon is 265 ft. How can you move the vertex on the left and make it narrower than 265 ft?
nikato
  • nikato
^I agree. and to find area of trapezoid (sum of bases/2) x height so the top would be [(125+265)/2]x 110
anonymous
  • anonymous
THis is what I am putting down for the top, am I correct? We know the top is 110 high (260-150), and then we do A=110*((265+125)/2 which adds up to 21450 square feet in the top trapezoid.
anonymous
  • anonymous
Ignore the missing parenthesis
nikato
  • nikato
yes. i got that for the top one too
ganeshie8
  • ganeshie8
Ahh so it doesn't matter where the left most vertex moves on the vertical line |dw:1433973606686:dw|
anonymous
  • anonymous
Awesome. SO now all we have left is the bottom?
ganeshie8
  • ganeshie8
(for area)
anonymous
  • anonymous
ANd we know the hegiht is 15, the base is 15, and the lid is 265
anonymous
  • anonymous
Right?
anonymous
  • anonymous
*150 instead of 15
mathstudent55
  • mathstudent55
Read my comment way above. We need to make two assumptions for this problem to be solvable with the info we are given.
anonymous
  • anonymous
Ya, I have to assume 150 for the sides
mathstudent55
  • mathstudent55
|dw:1433973761953:dw|
nikato
  • nikato
yes. that is true. now plug those numbers into the formula to find area. also if we dont assume these things, i dont think we have enough info
ganeshie8
  • ganeshie8
`The two side endpoints in the middle of the right and left sides must be at the same height.` this assumption is also not required right ?
mathstudent55
  • mathstudent55
If you do not make that assumption, you may not have two trapezoids.
ganeshie8
  • ganeshie8
doesn't matter, area wont change
mathstudent55
  • mathstudent55
We also need to assume that the top side and the bottom side are parallel to each other and parallel to the mid segment.
mathstudent55
  • mathstudent55
The area won;t change, but how will you calculate it if we do not deal with trapezoids?
ganeshie8
  • ganeshie8
that is a different problem haha
anonymous
  • anonymous
@ganeshie8, are you saying I have the wrong question?
mathstudent55
  • mathstudent55
@ganeshie8 Right. BTW, how do you copy a figure into the draw tool, and how do you edit it in color like you did above?
ganeshie8
  • ganeshie8
nope, im still trying to convince myself that the actuall question is valid as it stands
nikato
  • nikato
the bottom looks right. now just add the two areas together and you have solved your problem based on a lot of assumptions then
anonymous
  • anonymous
Whether or not the question is valid, I gotta write in something. I have 2 days to go before the simester ends and everything closes up, and since I got hit by a car on the 12th last month, I am behind around a week at this point.
anonymous
  • anonymous
To solve this, we cut the top into a trapezoid and the bottom into a trapezoid. We know the top is 110 high (260-150), and then we do A=110*((265+125)/2) which adds up to 21450 square feet in the top trapezoid. Bottom trapezoid has a base of 150, a height of 150, and a lid with a length of 265. 31125=150*((265+150)/2) Is this correct? Assuming we made all the agreed on assumptions that have to be done.
anonymous
  • anonymous
I think I have an answer, can I beg one of you to check it?
nikato
  • nikato
yea. that looks right. but i dont know why you call it a lid, instead of just the other base. and dont forget your last step, to add both the areas
anonymous
  • anonymous
Alright, thanks man.
anonymous
  • anonymous
I really do appreciate all your guys help. I was lost on this one.
anonymous
  • anonymous
I have another account if one of you guys wants another medal
ganeshie8
  • ganeshie8
Never do that. Medal the person that helps you most.
anonymous
  • anonymous
Youall helped me a ton. I gave the medal to Nikato, but thank you all.
mathstudent55
  • mathstudent55
You're welcome.
anonymous
  • anonymous
Should I close it, or did you guys want to continue talking?
ganeshie8
  • ganeshie8
It is okay to close as soon as you're done because you can't open a new question w/o closing the present q
anonymous
  • anonymous
Alright.

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