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bealiberty47
 one year ago
Math function rule question
bealiberty47
 one year ago
Math function rule question

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0First, look at the points you are given. Do they seem to be linear or not? To see if they are linear, see if the same change in x has the same change in y.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0If they are linear, then choose two points and find the equation of the line through them.

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.0There isn't a same change because while Y goes up x2, X goes down randomly

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.0So it's not linear?

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.0can you help me @geerky42

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0No. Don't compare with multiplication. Compare with subtraction.

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Try to plot its graph it clarify everything to you

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Here are the points: x 2 4 6 y 1 0 1

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0I will write the differences between each xcoordinate and the previous one on the line above the xcoordinates. I will do the same for the ycoordinates below the ycoordinates 2 2 x 2 4 6 y 1 0 1 1 1

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Notice that as x goes from 2 to 4, the difference is 2. As x goes from 4 to 6, the difference is again 2. Now look at y. As x goes from 2 to 4, y goes down by 1. As x goes from 4 to 6, y again goes down by 1. Every time x increases 2, y decreases 1. That is a linear relation.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Now that you see it's a linear relation, pick any two points. Then find the slope of the line between the two points. Do you know how to find the slope of a line given two points on the line?

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.0no please explain

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0For points \((x_1, y_1)\) and \((x_2, y_2) \), the slope opf the line through those points is: \(slope = m = \dfrac{y_2  y_1}{x_2  x_1} \) In other words, subtract the ycoordinates. Subtract the xcoordinates.. Divide the first difference by the second difference.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0That gives you slope. Then we have a little more work to find the equation.

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.0just give me a minute

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.04,0  2,1 = 1/2?

bealiberty47
 one year ago
Best ResponseYou've already chosen the best response.0or is it 2,1  4,0 = 1/2

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0If you use the points (4, 0) and (2, 1), you get: \(m = \dfrac{0  1}{4  2} = \dfrac{1}{2} = \dfrac{1}{2} \)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The slope is 1/2 Now we need to get the equation of the line. The slopeintercept form of the equation of t a line is \(y = mx + b\), where m = slope and b = yintercept. We know the slope is 1/2. We need to find b. We use one of our 3 points in the equation and solve for b. \(\color{red}{y} = \color{green}{m}\color{blue}{x} + \color{brown}{b}\) Let's use point \((\color{blue}{4}, \color{red}{0})\). We replace \(\color{blue}{x}\) with \(\color{blue}{4} \) and \(\color{red}{y} \) with \(\color{red}{0}\). We replace \(\color{green}{m}\) with \(\color{green}{\dfrac{1}{2}}\), since \(\color{green}{m}\) is the \(\color{green}{slope}\) and the \(\color{green}{slope}\) is \(\color{green}{ \dfrac{1}{2}} \). \(\color{red}{0} = \color{green}{\dfrac{1}{2}} (\color{blue}{4}) + \color{brown}{b}\) \(0 = 2 + b\) \(b = 2\) Now that we know b = 2, we can write the equation of the line: \(y = \dfrac{1}{2}x + 2\)
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