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anonymous

  • one year ago

Help! (k^2+8k+12) / (k^2 + 15k +54) * (k^2 +9k) / (k^2 +7k +10)

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  1. anonymous
    • one year ago
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    multiplying rational expressions

  2. Nnesha
    • one year ago
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    1st) factor all quadratic equations

  3. Nnesha
    • one year ago
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    \[\large\rm \frac{ k^2+8k+12 } { 9k^2 + 15k +54} * \frac{k^2 +9k} { k^2 +7k +10}\] factor all qudratic equation so you can cancel out some stuff do you know how to factor quadratic equations ?

  4. anonymous
    • one year ago
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    I got k/k+5 is that right?

  5. anonymous
    • one year ago
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    wait can you explain what happens to this

  6. anonymous
    • one year ago
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    |dw:1433974987628:dw|

  7. anonymous
    • one year ago
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    @Nnesha @ganeshie8

  8. Nnesha
    • one year ago
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    what's the common factor k^2 + 9k ???

  9. Nnesha
    • one year ago
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    what is common in those both terms ?

  10. anonymous
    • one year ago
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    They cross out once factored

  11. Nnesha
    • one year ago
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    alright k is common k^2 can be written as k times k \[\huge\rm k \times \color{ReD}{k} + 9\color{Red}{k}\] k is common so it out \[\large\rm \color{ReD}{k}(k+9)\]

  12. Nnesha
    • one year ago
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    \[\large\rm \frac{ k^2+8k+12 } { 9k^2 + 15k +54} * \frac{\color{Red}{k(k+9)}} { k^2 +7k +10}\] now can you factor quadratic equations k^2 +8k +12 ?

  13. anonymous
    • one year ago
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    yes give me a sec

  14. Nnesha
    • one year ago
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    alright :-)

  15. anonymous
    • one year ago
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    (k+6) (k+2) /(k+6) (k+9) * k (x+9) / (k+5) (k+2)

  16. Nnesha
    • one year ago
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    GREAT job!

  17. Nnesha
    • one year ago
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    i made a typo .-. :P \[\large\rm \frac{ k^2+8k+12 } { k^2 + 15k +54} * \frac{\color{Red}{k(k+9)}} { k^2 +7k +10}\] here is it k^2 +15k +54 ?? denominator of first fraction ?

  18. Nnesha
    • one year ago
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    yes it's i typed 9 instead of ( <-- parentheses sorry about that

  19. Nnesha
    • one year ago
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    \[ \huge\rm \frac{(k+6) (k+2)}{(k+6) (k+9) }* \frac{ k (x+9) }{ (k+5) (k+2)} \] cancel!

  20. anonymous
    • one year ago
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    ok so k/x=+5

  21. anonymous
    • one year ago
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    k/x+5

  22. anonymous
    • one year ago
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    thanlks!!!

  23. Nnesha
    • one year ago
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    \[ \huge\rm \frac{\cancel{(k+6)} \cancel{ (k+2)}}{\cancel{(k+6)} \cancel{\cancel{(k+9)}} }* \frac{ k \cancel{(x+9)} }{ (k+5) \cancel{(k+2)}} \] \[\large\rm \frac{ k }{ k+2 }\] yep right!

  24. Nnesha
    • one year ago
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    my pleasure!! :-)

  25. anonymous
    • one year ago
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    yay! thanks! super helpful

  26. Nnesha
    • one year ago
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    thanks great work!

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