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Identify the factors of x2 - 4x - 21.

Hi. To get the factors of x^2 - 4x - 21, let's put this equation into factored form.

To start, please identify the a, b, and c components of this quadratic equation.

Alright, would the A be x^2, B=4x, C=-21

Very close, but more precisely, A and B will need to describe the coefficients of the x factors.

B will be 4, A will be 1.

Is this clear to you?

Yeah, so far it is

2 x-intercepts?

That's exactly correct!

No, I don't sorry.

That's no problem at all.

Have you been taught about FOIL or expanding something that looks like:
(x+1)(x-1)?

Yeah, I have

So if I use FOIL on an example:
(x + 3)(x + 4)
I get: x^2 + 3x + 4x + 12
Which equals: x^2 + 7x + 12

Do you see how that matches the shape of your formula?

We need to go from your formula into factored form.

Am I being clear? Please let me know if I'm being confusing

Great.
So let's look at your equation: x2 - 4x - 21

Let's learn what we know about FOILing and try to work backwards.

|dw:1433976603608:dw|

|dw:1433976690825:dw|

And then do you subtract the 1x to the 3x?

Not quite.

So I cross them out then?

|dw:1433976867455:dw|

We start off by setting up our two factors:
(X)(X)
Multiplying these two now would give us X^2.

Sorry, I think I am being unclear. That is not the answer to your problem:
x2 - 4x - 21

That was an example.

Oh. Sorry again. I see what you mean. Text is really hard today for some reason.

Yeah, haha it's okay.

We're basically trying to take X^2 + 4X + 3 and shove it into (x + something)(x + something) form.

We still have to take care of the 4X and the +3.

Does this make any sense?