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anonymous

  • one year ago

Graph the function by starting with the graph of the basic function and then using the techniques of shifting, compressing, stretching, and /or reflecting. Graph one transformation in each coordinate system. Label each graph. f(x)=-2(x+1)^2+4

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    I would use something like desmos https://www.desmos.com/calculator to graph

  3. jim_thompson5910
    • one year ago
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    type into the first line y = x^2 this is the parent function

  4. anonymous
    • one year ago
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    Okay!

  5. jim_thompson5910
    • one year ago
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    then you'll shift the graph 1 unit to the left to get y = (x+1)^2 after that, you will multiply the (x+1)^2 term with -2 to get y = -2(x+1)^2. This will reflect the graph over the x axis and vertically stretch the graph by a factor of 2

  6. anonymous
    • one year ago
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    I have that already on one coordinate plane.

  7. anonymous
    • one year ago
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    Would shifting be in another coordinate plane?

  8. jim_thompson5910
    • one year ago
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    finally, you will add 4 to get y = -2(x+1)^2+4 this shifts the graph 4 units up

  9. jim_thompson5910
    • one year ago
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    each time you do a transformation, you will have it on its own xy axis

  10. anonymous
    • one year ago
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    I do not understand how do I show this on the (x,y)

  11. jim_thompson5910
    • one year ago
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    this is what it looks like if you did all equations I mentioned above on the same xy axis

  12. jim_thompson5910
    • one year ago
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    imagine each of those parabolas gets its own xy coordinate system

  13. anonymous
    • one year ago
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    I understand but my teacher wants us to show the change meaning when we plug in -1, 0 and 1

  14. anonymous
    • one year ago
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    I did get what you got, on each coordinate plane but I have to be able to show the process.

  15. jim_thompson5910
    • one year ago
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    so he wants you to plug those x values into each equation?

  16. anonymous
    • one year ago
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    basically

  17. jim_thompson5910
    • one year ago
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    you can create a table using desmos click on the equation you want to work with then click the gear icon I suggest duplicating the graph, so do so, but it's not mandatory then turn that duplicate graph into a table

  18. jim_thompson5910
    • one year ago
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  19. jim_thompson5910
    • one year ago
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    you can add or subtract x values from the table or change the x values that are already there the table will update itself with each change or addition in x

  20. anonymous
    • one year ago
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    Thank you! Now i got it! Are you able to help me with three more questions?

  21. jim_thompson5910
    • one year ago
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    it depends how long they are, but we'll see

  22. anonymous
    • one year ago
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    Okay, Suppose the point (2,4) is on the graph of y=f(x). Find a point on the graph of the given function . The reflection of the graph of y=f(x) across the y-axis

  23. jim_thompson5910
    • one year ago
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    Rule: reflecting any point (x,y) over the y axis will result in (-x,y)

  24. anonymous
    • one year ago
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    What does the question ask?

  25. jim_thompson5910
    • one year ago
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    it just wants you to reflect (2,4) over the y axis

  26. anonymous
    • one year ago
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    How would I do this?

  27. anonymous
    • one year ago
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    By graphing?

  28. jim_thompson5910
    • one year ago
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    by using that rule I posted

  29. anonymous
    • one year ago
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    So instead of 2,4 it would be -2,4

  30. jim_thompson5910
    • one year ago
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    (-2,4) don't forget the parenthesis

  31. anonymous
    • one year ago
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    Yes, and Would I graph this?

  32. jim_thompson5910
    • one year ago
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    you can if you want they just want you to find the point

  33. anonymous
    • one year ago
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    Okay , next question Solve the problem, If f(x)= x-3A/3x+5 and f(3)=6. what is the value of A?

  34. anonymous
    • one year ago
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    are you able to help me?

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