Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two, solve for f(g(x)) when x = 1.

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Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two, solve for f(g(x)) when x = 1.

Mathematics
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This? \[g(x)=\frac{ x-3 }{ 2}\]
my options are -1 0 3 4
Is that the right equation for g(x)?

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Other answers:

idk :(
yes it is.
then you'll plug in 1 for x in the g(x) equation. then input the answer to that equation into the x variables for the f(x) equation
so I have to plug -1 into the f(x)
yup.
I get 2..is that right? im so lost

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