anonymous
  • anonymous
SIMPLIFY x/x^2 + 6x/ x-x^2 I need help..
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@tysonw @ganeshie8 @jim_thompson5910
anonymous
  • anonymous
\[\frac{ x }{ x^2 }+\frac{ 6x }{ x(1-x) }\] Once you factor you can see the the common denominator is x²(1-x). Multiply the first fraction by (1-x)/(1-x) and the second by x/x to get a single denominator. \[\frac{ x(1-x) }{ x^2(1-x) }+\frac{ 6x(x) }{ x(1-x)(x) }\]
anonymous
  • anonymous
\[\frac{ x-x^2+6x^2 }{ x^2(1-x)}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
can you simplify from here?
anonymous
  • anonymous
yes give me sec :)
anonymous
  • anonymous
-5x+6/(x-1) (x+1)
anonymous
  • anonymous
not sure what you did. The denominator was already factored. Combine like terms in the numerator, then factor it.
anonymous
  • anonymous
Can you step by step @peachpl
anonymous
  • anonymous
Picking up from the last equation I posted |dw:1433981590135:dw|
anonymous
  • anonymous
|dw:1433981692809:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.