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anonymous
 one year ago
Solve each equation on the interval [0,2π):
a. 4sin2x – 3 = 0
b. cos(3x) = 1
anonymous
 one year ago
Solve each equation on the interval [0,2π): a. 4sin2x – 3 = 0 b. cos(3x) = 1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@freckles @IrishBoy123 @ganeshie8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk how to do this hun. sorry.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@e.mccormick is offline btw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi I'm assuming you don't know how to do this either??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@TheSmartOne @whpalmer4

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0a. \(4sin2x – 3 = 0\) thus: \(4sin2x = 3\) you can finish that off with your calculator. solve for '2x' first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, so do I solve 4sin(2x) with my calculator? What about the " = 3" that you put. Should the answer to 4sin(2x) be my answer to "a"? What about b? @IrishBoy123

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can yo u help with my questinon

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@logan6767 depends on what your question is...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following points lie in the solution set to the following system of inequalities? y less than or greater to x  5 y less than or greater to x  4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(1, 10) (1, 10) (10, 1) (1, 10)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, can't solve it @logan6767

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04 sin (2x)  3 = 0 4 sin (2x) = 3 sin (2x) = 3/4 2x = arcsin (3/4) → this is the 1st quadrant solution for 2x x = ½ arcsin (3/4) 2x = π  arcsin (3/4) → this is the 2nd quadrant solution for 2x x = ½(π  arcsin (3/4)) If 0<x<2π, then 0<2x<4π, so other solutions for 2x are 2x = 2π + arcsin (3/4) x = π + ½ arcsin (3/4) 2x = 3π  arcsin (3/4) x = ½(3π  arcsin (3/4))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is this correct or are you guessing??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So a has 6 solutions?: 2x = 2π + arcsin (3/4) x = π + ½ arcsin (3/4) 2x = 3π  arcsin (3/4) x = ½(3π  arcsin (3/4)) x = ½ arcsin (3/4) x = ½(π  arcsin (3/4)) Or 4 solutions?: x = π + ½ arcsin (3/4) x = ½(3π  arcsin (3/4)) x = ½ arcsin (3/4) x = ½(π  arcsin (3/4)) @peachpi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, but what about b??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The angle here is 3x, so the interval is [0, 6π). Pull out your unit circle and find the angle that has a cosine of 1. Then add 2π twice to get the other 2 solutions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do I add 2pi to the 1 or to the angle that has a cosine of 1?
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