anonymous
  • anonymous
Solve each equation on the interval [0,2π): a. 4sin2x – 3 = 0 b. cos(3x) = -1
Mathematics
katieb
  • katieb
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anonymous
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anonymous
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anonymous
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anonymous
  • anonymous
anonymous
  • anonymous
idk how to do this hun. sorry.
anonymous
  • anonymous
@e.mccormick
anonymous
  • anonymous
it's okay
anonymous
  • anonymous
@e.mccormick is offline btw
anonymous
  • anonymous
@peachpi I'm assuming you don't know how to do this either??
anonymous
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IrishBoy123
  • IrishBoy123
a. \(4sin2x – 3 = 0\) thus: \(4sin2x = 3\) you can finish that off with your calculator. solve for '2x' first.
anonymous
  • anonymous
Wait, so do I solve 4sin(2x) with my calculator? What about the " = 3" that you put. Should the answer to 4sin(2x) be my answer to "a"? What about b? @IrishBoy123
anonymous
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anonymous
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anonymous
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anonymous
  • anonymous
can yo u help with my questinon
GenTorr
  • GenTorr
i can try
anonymous
  • anonymous
@logan6767 depends on what your question is...
anonymous
  • anonymous
Which of the following points lie in the solution set to the following system of inequalities? y less than or greater to x - 5 y less than or greater to -x - 4
anonymous
  • anonymous
(1, 10) (-1, 10) (10, 1) (1, -10)
anonymous
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anonymous
  • anonymous
Sorry, can't solve it @logan6767
anonymous
  • anonymous
anonymous
  • anonymous
4 sin (2x) - 3 = 0 4 sin (2x) = 3 sin (2x) = 3/4 2x = arcsin (3/4) → this is the 1st quadrant solution for 2x x = ½ arcsin (3/4) 2x = π - arcsin (3/4) → this is the 2nd quadrant solution for 2x x = ½(π - arcsin (3/4)) If 0
anonymous
  • anonymous
Is this correct or are you guessing??
anonymous
  • anonymous
and I'm out
anonymous
  • anonymous
what about b?
anonymous
  • anonymous
So a has 6 solutions?: 2x = 2π + arcsin (3/4) x = π + ½ arcsin (3/4) 2x = 3π - arcsin (3/4) x = ½(3π - arcsin (3/4)) x = ½ arcsin (3/4) x = ½(π - arcsin (3/4)) Or 4 solutions?: x = π + ½ arcsin (3/4) x = ½(3π - arcsin (3/4)) x = ½ arcsin (3/4) x = ½(π - arcsin (3/4)) @peachpi
anonymous
  • anonymous
4
anonymous
  • anonymous
okay, but what about b??
anonymous
  • anonymous
The angle here is 3x, so the interval is [0, 6π). Pull out your unit circle and find the angle that has a cosine of -1. Then add 2π twice to get the other 2 solutions
anonymous
  • anonymous
Do I add 2pi to the -1 or to the angle that has a cosine of -1?

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