hrm, from the info given I have a_20=a+(20-1)d a_20=a+(19)*3 a_20=a+57 yeah?
we know a_20 so it comes to 101=a+19(3) a=44 so the formula for the nth term will be a_n=44+(n-1)(3) ?
You've put a lot of work into this already, so let's test your equation to verify it.
Testing a_20 seems like a good idea. Do we get the right answer?
And.... we do!
Looks like you've got it. Congrats!
thanks for checking ^-^ (how did you test a_20?)
Just plugged in n = 20.
I hoped it would be 101 as the answer, and it was.
oh haha I see. Fabulous.
Of course, I needed to see that n = 1 gave me 44 as claimed, but that was kind of obvious since that's what you built the formula to do. :)