vera_ewing
  • vera_ewing
Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall. Approximately what percent of the adult male population is taller than the average basketball player?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jtvatsim
  • jtvatsim
Do you have access to a normal distribution table or graph? You will probably either need that or have the percentages for different standard deviations memorized...
jtvatsim
  • jtvatsim
Hmm... seems off somewhat, since the question wants the percentage taller than the average basket ball player. Almost everyone is taller? :)
vera_ewing
  • vera_ewing
Oops I mean 49.87%

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jtvatsim
  • jtvatsim
Alright, these tables are a bit weird, so let me double check what I'm doing. :)
jtvatsim
  • jtvatsim
|dw:1433985935709:dw|
jtvatsim
  • jtvatsim
The population taller than this amount is this area...
jtvatsim
  • jtvatsim
|dw:1433986002610:dw|
jtvatsim
  • jtvatsim
Since we know that to the left is 99.865% it follows that the remaining area to the right adds up to 100%. This means that the area we seek is 100 - 99.865 = 0.135%
jtvatsim
  • jtvatsim
Does that make sense? :)

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