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anonymous
 one year ago
Help solve please medal! Simplify
3x+10/ x+1 + x+3/x+4 6x+27/(x+1)(x+4)
anonymous
 one year ago
Help solve please medal! Simplify 3x+10/ x+1 + x+3/x+4 6x+27/(x+1)(x+4)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@radar @sammixboo @MrNood @puppylife101

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Yungwisdom2000 @Compassionate

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1I'm going to rewrite this to make sure we are looking at the same thing. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{3x+10}{ x+1} + \frac{ x+3}{x+4}  \frac{6x+27}{(x+1)(x+4)}\] Is that the right thing?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1It's a bit scary looking. :) Any thoughts on what you might do first?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we need a common denominator right :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1That would be REALLY nice. Yes, let's try that.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1What might be the common denominator we are trying to make?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Seems like a good choice. That appears to be the most complicated thing in our expression. So far, so good.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1So, let's look at the first fraction. What needs to be done here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03x+10 (x+4) / x+1 (x+4) + (x+3) (x+1) / (x+4)(x+4) right

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Yes, on the second fraction you mean (x + 1) on the bottom, but I get it. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Great! So here's what we have so far.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{(3x+10) (x + 4)}{(x+1) (x + 4)}+\frac{(x+3)(x+1)}{(x+1)(x+4)}−\frac{6x+27}{(x+1)(x+4)}\]

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Wow, that's a lot of stuff. Now what?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Well, if we "cancel out" that might put us right back where we started right? Unless you mean distribute...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm sorry i meant distribute lol

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1No worries. :) Let's try to do that. What do you get. (Might take a minute) :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im kinda lost can you draw it out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0from where we left off

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Sure! I think we were here right? \[\frac{(3x+10)(x+4)}{(x+1)(x+4)}+\frac{(x+3)(x+1)}{(x+1)(x+4)}−\frac{6x+27}{(x+1)(x+4)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes ok, so we distribute

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Yes, and what do you get after that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 4/ (x+1) (x+4)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.14 for which fraction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think i did something wrong

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Oh, ok, let me double check that. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1So, for the first fraction: \[\frac{(3x+10)(x+4)}{(x+1)(x+4)}=\frac{3x^2 + 12x + 10 x + 40}{(x+1)(x+4)}\]

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1For the second fraction: \[\frac{(x+3)(x+1)}{(x+1)(x+4)} = \frac{x^2 + 3x + x + 3}{(x+1)(x+4)}\]

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1For the third fraction (watch out for the tricky  sign!): \[\frac{6x+27}{(x+1)(x+4)}=\frac{6x27}{(x+1)(x+4)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i got 1/ (x+4)(x+1) for final

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1I get: (3x^2 + x^2 + 22x + 4x  6x + 40 + 3  27)/(x+1)(x+4) so (4x^2 + 20x + 16)/(x+1)(x+4) so (2x + 2)(2x + 8)/(x+1)(x+4) then 2(x+1)*2(x+4)/(x+1)(x+4) Oh wow! 4 is the final answer. I think. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i see, now you factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey do you mind checking this one for me
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