• anonymous
@jvatsim ok so x1 = 3*x2 is the next problem so that means (3,1)^T (6,2)^T etc so nonempty here x1=3*x2 the next step alphaX so x = (3x2, x2)^T so alpha *x means (alpha*3*x2, alphax2)^T and that equals alpha*3*x2 = alpha *x2 equals alpha(3*x2 = x2) so it passes and on to step 3 x + y so here so i say x = (3x2,x2)^t y = (3y2, y2)^t we can still say 3x2+3y2 is = x2 + y2 ?? i think im missing something on this las step
Linear Algebra
• Stacey Warren - Expert brainly.com
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SOLVED
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