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Sounds good, be back. :)

a_6=496feet

^ (part a)

b) the formula would be
a_n=16+(n-1)(32)

Testing it with a_2 the formula seems to be correct :)

I got the same thing for b, but 576 for a

hmm let's see where I might've messed up
a_6=16 +(6-1)(32) correct yeah?

to find the 6th term, yes. But I think it's asking for the sum of the first 6 terms

oooh, wow. I completely missed that.

so i must find a_4 and a_5

a_4=112, a_5 = 144

oh o.0

Yes those are right

hm but I should probably use that formula you just used because the prof introduced it to us.

a_6=176 correct?

yes

so we have
s_6=(6/3)(16+176)
=3(192)
=576

yep

Fantastic! thank you so much :)

you're welcome!

my formula is not for the sum

Right?
So the formula would actually be
s_n=(n/2)(16+a_n)

right, and you'd so substitute the formula for the nth term for a_n

If you need an explicit formula

ok, it just asks for a formula that could generate any nth term.

Er, should I put the formula to find
a_n
and also the formula for finding the sums?

does that make sense? can't really think of a right way to say it

you mean
sn=n/6(16+(n-1)(32))
(not ^3)

ahh yes I see what you did.

oh, yes. n/2

ok :)

thanks, phew. That was close. I almost put the wrong formula xP

Sn = (n/2)(16 + 16+(n-1)(32))
is the final formula?

yes. I mean you can do some algebra to make it prettier, but it's correct

oh o.0 we should probably make it prettier.. hah

sn=(n/2)(16+512(n-1))
is that still correct? and simplified enough?

keep going until you get a quadratic, so distribute 512 and combine like terms

wait no!

|dw:1433989465521:dw|

aiai too simplified we never did that in class hrm

maybe up to the second thing you did

(n/2)(32+(n-1)(32))

does that work?

yes

ah ok. I think thats simplified enough o.0

cool