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  • one year ago

Gaseous C2H4 reacts with O2 according to the following equation: C2H4 (g) + 302 -> 2CO2 + H2O (g) What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4? A) 17.3 L B) 42.9 L C) 3.86 x 10^2 L D) 1.29 x 10^2 L E) Not enough information is given to solve the problem.

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  1. anonymous
    • one year ago
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    1) The reaction is not well balanced. It produce 2H2O. Anyway will not affect your calculations in this problem. 2) according to the stoicheometry for each mole of C2H4 you need 3 moles of O2, then, for 5.75 mol C2H4 you will need 3 times more, 5.75 x 3= 17.25 moles of O2. 3) one mole of any gas at STP conditions will occupy 22.4 L. Do the math! I guess will be C or D that you forgot to put the values

  2. hpfan101
    • one year ago
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    Ok, thank you! Oh, I didn't realize I forgot to put in the values for C & D. My bad.

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