anonymous
  • anonymous
Rational expressions 15xy/x^2-y^2 - X-Y/X+Y
Mathematics
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anonymous
  • anonymous
Rational expressions 15xy/x^2-y^2 - X-Y/X+Y
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Nnesha
  • Nnesha
\[\huge\rm \frac{ 15xy }{ x^2-y^2} - \frac{ x-y }{ x+y }\] like this ?
Nnesha
  • Nnesha
if yes remember difference of square \[\huge\rm a^2 -b^2 = (a+b)(a-b)\] 2nd step ) find common denominator

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Nnesha
  • Nnesha
3rd) cancel some stuff 4th) done!
anonymous
  • anonymous
@Nnesha Can you show a step by step i've been stuck for hours
anonymous
  • anonymous
@Nnesha Can you show a step by step i've been stuck for hours
Nnesha
  • Nnesha
oky i have 5 mints let's see :-) so x ^2 - y^2 = ???
Nnesha
  • Nnesha
difference of square^
anonymous
  • anonymous
(x+y)(x-y)?
Nnesha
  • Nnesha
yes right!
Nnesha
  • Nnesha
now find common factor
Nnesha
  • Nnesha
\[\huge\rm \frac{ 15xy - (x-y)(x+y)}{ (x+y)(x-y) }\] now solve x+y are same at both denominator so just write on time and x-y is a common denominator multiply top part with( x+y) denominator of first fraction is same as common denominator so t 15xy stay same
Nnesha
  • Nnesha
got it ??
Nnesha
  • Nnesha
now just solve the numerator

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