anonymous
  • anonymous
2y+3/y = 3/2 rational expression help
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
@Ashleyisakitty @poopsiedoodle @whpalmer4 @blahhedup101
freckles
  • freckles
are you trying to solve an equation?
freckles
  • freckles
\[2y+\frac{3}{y}=\frac{3}{2} \\ \text{ multiply both sides by } y \neq 0 \\ y(2y+\frac{3}{y})=y(\frac{3}{2} )\\ y(2y)+y(\frac{3}{y})=\frac{3}{2}y \\ 2y^2+3=\frac{3}{2} y \\ \text{ if you don't want \to deal with any fractions multiply both sides by 2 } \\ 4y^2+6=3y \\ \text{ subtract} 3y \text{ on both sides } 4y^2-3y+6=0\] you have a quadratic equation to solve. but the equation you wrote is probably not the equation you meant you probably meant \[\frac{2y+3}{y}=\frac{3}{2}\] though I could be wrong about that too you did say rational expression after all and you have an equation composed of rational expressions on left and right side

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freckles
  • freckles
and if you meant the last equation I wrote which is (2y+3)/y=3/2 I would still multiply both sides by y and 2
freckles
  • freckles
\[2(2y+3)=3(y) \\ 4y+6=3y \]
anonymous
  • anonymous
@freckles than what
freckles
  • freckles
you solve for y
freckles
  • freckles
And I still don't know what equation you mean
anonymous
  • anonymous
@freckles The second equation you showed
freckles
  • freckles
ok do something to get your y terms on one side
anonymous
  • anonymous
@freckles Thanks
freckles
  • freckles
what did you get?
freckles
  • freckles
\[2(2y+3)=3(y) \\ 4y+6=3y\] You subtracted 4y on both sides right?

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