anonymous
  • anonymous
Which logarithmic graph can be used to approximate the value of y in the equation 2^y = 3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/53e5437ee4b0e7ddacf67cf4-sophiagriffin-1407533986214-screenshot20140808at5.39.07pm.png
anonymous
  • anonymous
@johnweldon1993 @kohai @KyanTheDoodle @Loser66
anonymous
  • anonymous
@sasogeek

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anonymous
  • anonymous
@Luigi0210 @Whitemonsterbunny17
KyanTheDoodle
  • KyanTheDoodle
Honestly, I have no idea.
anonymous
  • anonymous
it's alright @KyanTheDoodle , thank you
anonymous
  • anonymous
If the y was an x, do you know what the graph would look like?
anonymous
  • anonymous
No
anonymous
  • anonymous
Let's identify what we know. Is 2^y ever negative? Is it ever 0?
anonymous
  • anonymous
No
anonymous
  • anonymous
What happens as y gets larger? What happens when y is negative?
anonymous
  • anonymous
if it's negative the graph goes down i think and the exponent determines which way it goes,
anonymous
  • anonymous
With a larger and larger negative exponent, it gets closer and closer to 0. With a larger and larger positive exponent, it gets larger and larger. So, we're looking for the graph that never results in a negative x value. It gets closer to 0 with the larger negative y, and gets further and further from the y axis as y gets larger. Which of the graphs follows this pattern?
anonymous
  • anonymous
I eliminated B and c because they look they're getting close to zero and D is increasing in y value but to the negative so i think the answer is "A"
anonymous
  • anonymous
A goes into the negative x values, so it can't be A. So does D.
anonymous
  • anonymous
Is B increasing in y value the most?
anonymous
  • anonymous
I'm not sure what you mean by that. We're looking for the graph of the equation: 2^y We know what this will do in certain situations (such as it will never go negative). This means we can eliminate graphs A and D, as the line shown on there goes into negative X values.
anonymous
  • anonymous
After that, we can look at 2^1 = 2 and 2^0 = 1 to eliminate one of the other two graphs.
anonymous
  • anonymous
why did you have them to the ^1 and ^0
anonymous
  • anonymous
Those are the results when y = 1 and y = 0. We can see which graph of the remaining two goes through the correct points. y = 0: 2^0 = 1 So we look for the point where x=1 and y=0, and see if the graph goes through that point.
anonymous
  • anonymous
i see that in C
anonymous
  • anonymous
i'm sorry for taking long my internet connection was slow
anonymous
  • anonymous
@Vandreigan
anonymous
  • anonymous
Yep, C. It follows all the patterns :)
anonymous
  • anonymous
alright, thank you so much for your help.. i appreciate it @Vandreigan
anonymous
  • anonymous
My pleasure :)

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