- anonymous

Which logarithmic graph can be used to approximate the value of y in the equation 2^y = 3?

- schrodinger

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- anonymous

http://assets.openstudy.com/updates/attachments/53e5437ee4b0e7ddacf67cf4-sophiagriffin-1407533986214-screenshot20140808at5.39.07pm.png

- anonymous

- anonymous

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## More answers

- anonymous

- KyanTheDoodle

Honestly, I have no idea.

- anonymous

it's alright @KyanTheDoodle , thank you

- anonymous

If the y was an x, do you know what the graph would look like?

- anonymous

No

- anonymous

Let's identify what we know. Is 2^y ever negative? Is it ever 0?

- anonymous

No

- anonymous

What happens as y gets larger? What happens when y is negative?

- anonymous

if it's negative the graph goes down i think and the exponent determines which way it goes,

- anonymous

With a larger and larger negative exponent, it gets closer and closer to 0.
With a larger and larger positive exponent, it gets larger and larger.
So, we're looking for the graph that never results in a negative x value. It gets closer to 0 with the larger negative y, and gets further and further from the y axis as y gets larger.
Which of the graphs follows this pattern?

- anonymous

I eliminated B and c because they look they're getting close to zero and D is increasing in y value but to the negative so i think the answer is "A"

- anonymous

A goes into the negative x values, so it can't be A. So does D.

- anonymous

Is B increasing in y value the most?

- anonymous

I'm not sure what you mean by that.
We're looking for the graph of the equation: 2^y
We know what this will do in certain situations (such as it will never go negative).
This means we can eliminate graphs A and D, as the line shown on there goes into negative X values.

- anonymous

After that, we can look at 2^1 = 2 and 2^0 = 1 to eliminate one of the other two graphs.

- anonymous

why did you have them to the ^1 and ^0

- anonymous

Those are the results when y = 1 and y = 0. We can see which graph of the remaining two goes through the correct points.
y = 0: 2^0 = 1
So we look for the point where x=1 and y=0, and see if the graph goes through that point.

- anonymous

i see that in C

- anonymous

i'm sorry for taking long my internet connection was slow

- anonymous

- anonymous

Yep, C. It follows all the patterns :)

- anonymous

alright, thank you so much for your help.. i appreciate it @Vandreigan

- anonymous

My pleasure :)

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