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Blondisaurus

  • one year ago

Reduce to lowest terms: (Equation In Comments)

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  1. Blondisaurus
    • one year ago
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    \[\frac{ 2^{2}-3x-2 }{ 10+x-3x ^{2} }\]

  2. Blondisaurus
    • one year ago
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    Thats 2x to the second power above sorry

  3. anonymous
    • one year ago
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    The numerator 2x^2 -3x -2 can be factored by grouping: The coefficient of 2 multiplied by -2 = -4. We need 2 numbers so that when multiplied = -4 and the sum = -3. (-3x is the 2nd term in the numerator.) 1(-4) = -4 1-4 =-3 Since -4x + 1x = -3x This can be re-written as 2x^2 -4x +x -2 when factored by grouping we get 2x(x - 2) +1(x - 2) when factored further we get (2x + 1)(x -2)

  4. anonymous
    • one year ago
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    The denominator can be re-written as -3x^2 + x + 10 -3(10) = -30 -5(6) = -30 -5 + 6 = 1 Therefore it can be re-written as -3x^2 +6x -5x + 10 When factored it equals -3x(x - 2) -5(x - 2) When factored further it equals (-3x - 5)(x - 2)

  5. anonymous
    • one year ago
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    So we get \[\frac{ (2x + 1)(x - 2) }{ -1(3x + 5)(x -2) }\] the x - 2 in the numerator and denominator cancel each other out

  6. Blondisaurus
    • one year ago
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    Thank you very much!

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