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anonymous
 one year ago
How could I go about solving this problem:
If x^2+y^2=25 and dy/dt=6, find dx/dt when y=4 and x=3.
anonymous
 one year ago
How could I go about solving this problem: If x^2+y^2=25 and dy/dt=6, find dx/dt when y=4 and x=3.

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[2x \frac{ dx }{ dt } + 2y \frac{ dy }{ dt } = 0\] differentiate both sides wrt to t. Now find dx/dt and plug in the values.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh okay! Thanks so much! :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2It's implicit differentiation :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right! I always get confused about the "with respect to..." part xD but I got what you did here! :D

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You may have got confused because you may not be used to differentiating with respect to t, which just means x and y are functions of t :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ahhh that's true! That makes total sense haha XD
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