MEDALS AND FAN WITHIN FEW MINUTES Carlisle conducted an experiment to determine if the there is a difference in mean body temperature for men and women. He found that the mean body temperature for a sample of 100 men was 97.9 with a population standard deviation of 0.57 and the mean body temperature for a sample of 100 women was 98.6 with a population standard deviation of 0.55. Assuming the population of body temperatures for men and women is normally distributed, calculate the 99% confidence interval and the margin of error for the mean body temperature for both men and women. Using compl

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MEDALS AND FAN WITHIN FEW MINUTES Carlisle conducted an experiment to determine if the there is a difference in mean body temperature for men and women. He found that the mean body temperature for a sample of 100 men was 97.9 with a population standard deviation of 0.57 and the mean body temperature for a sample of 100 women was 98.6 with a population standard deviation of 0.55. Assuming the population of body temperatures for men and women is normally distributed, calculate the 99% confidence interval and the margin of error for the mean body temperature for both men and women. Using compl

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really not looking to get all wordy, someone just help me get the answer please
The formula that you need for the confidence intervals is: \[\large \bar {x}\pm2.576\frac{\sigma}{\sqrt{n}}\]
The margin of error is given by: \[\large 2.576\frac{\sigma}{\sqrt{n}}\]

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