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I'm sorry, those functions are messed up, let me fix that.

f(x)=x+a/b
g(x)=cx-d

So, for part 1, I have f(x)=x+3/5 and g(x)=5x-3. I'm not sure of what I'm doing in parts 2 and 3.

is f(x)
\[ f(x) = \frac{x+a}{b} \]?

yes.

so we could write
\[ f(x) = \frac{1}{b} x + \frac{a}{b} \]

For which part?

ok

you should get
\[ f( g(x) ) = \frac{( 5x-3 +3)}{5} \]

now simplify that.
For part 3, do almost the same thing
show g( f(x) ) = x

ok

And I am so sorry, I was gone for a moment.

Ok, so that's what I got for that part.

So for part 3, to I basically just solve it to show g( f(x) ) = x?

Because I worked it out and got it. Is that what I want to turn in for part 3, my work?

I assume for part 2, you got f( g(x))= x after simplifying?

\[ f( g(x) ) = \frac{( 5x-3 +3)}{5} = \frac{5x+0}{5} = \frac{5x}{5} = x \]

yes. That's my work exactly.

g(f(x))=5(x+3/5)-3
Then the 3's will cancel each other out, and so will the 5's, to get g(f(x))=x.

oh, sorry

So then it will x+3/1 or 0? And then after that, the 3's will still cancel out, right?

just like
\[ \frac{15}{5} = \frac{5 \cdot 3 }{5} = \frac{5}{5} \cdot 3 = 1 \cdot 3 = 3\]

ok, that makes sense.

ok, thanks.

By the way, any suggestions for an online graph?

I downloaded geogebra.

Okay, I'll download it too.

So, graph 5 points for each?

if you use geogebra
you type in
f(x)= (x+3)/5
and it will plot the line

ok

Got it, thanks!

I have one more question, want me to make a new thread?

thank you :D