A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Lyra and Donna are testing the twoway radios they built for their high school science project. Lyra goes to the top of a building that is 22 meters high with one of the radios and stands directly above the building’s entrance. Donna walks out of the entrance, perpendicular to the building, with the other radio. If Donna is more than 50 meters from the entrance, the connection between the radios breaks. What is the range of communication for the two radios to the nearest meter?
50 meters
55 meters
62 meters
72 meters
anonymous
 one year ago
Lyra and Donna are testing the twoway radios they built for their high school science project. Lyra goes to the top of a building that is 22 meters high with one of the radios and stands directly above the building’s entrance. Donna walks out of the entrance, perpendicular to the building, with the other radio. If Donna is more than 50 meters from the entrance, the connection between the radios breaks. What is the range of communication for the two radios to the nearest meter? 50 meters 55 meters 62 meters 72 meters

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill give you a medal.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First, set up a diagram as shown. dw:1434030018717:dw You want to assume the maximum (50m) since you are trying to find the range of communication: as in, the MAXIMUM range of communication. Now simply use the pythagorean theorem to find the hypotenuse. Here, "c" represents the hypotenuse. Keep in mind that the hypotenuse represents the range. \[a^2+b^2=c^2\] \[22^2+50^2=c^2\] \[\sqrt{22^2+50^2}=\sqrt{c}\] \[54.6=c\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.