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anonymous

  • one year ago

Will give medal! Use the information below to find the missing measure such that ABC ~ DEF. AB = 35, DE = 14, DF = 22, m<A = m<D = 57, AC = ? A. 27 B. 43 C. 55 D. 70

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  1. johnweldon1993
    • one year ago
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    So i'm assuming it would just look like |dw:1434033084873:dw|

  2. johnweldon1993
    • one year ago
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    Since we want these to be similar...the length of the first object would just be a factor of the second one So Length AB = Something * Length DE Length AC = Same Something * Length DF Our job is to find out what that "something" is

  3. anonymous
    • one year ago
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    to find what AC is

  4. johnweldon1993
    • one year ago
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    Ultimately yes, but for now we need to find out what the "something" is as I have described above \[\large AB = xDE \] \[\large 35 = x(14)\] what is 'x' there?

  5. anonymous
    • one year ago
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    will it be a decimal?

  6. johnweldon1993
    • one year ago
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    It will be yes 35 divided by 14 is a decimal number

  7. anonymous
    • one year ago
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    2.5

  8. johnweldon1993
    • one year ago
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    Right....so that means for the lengths AB and DE......AB is 2.5 times bigger than DE Which is what we need because since these are to be "similar" that means the other sides will be subject to the same factor That means that AC would ALSO be 2.5 times bigger than DF...so what would AC be?

  9. anonymous
    • one year ago
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    Multiply 2.5 x 2?

  10. johnweldon1993
    • one year ago
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    Well...22 but yes

  11. anonymous
    • one year ago
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    I got the answer 55?

  12. johnweldon1993
    • one year ago
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    Correct! :)

  13. anonymous
    • one year ago
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    ty

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