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anonymous
 one year ago
Will give medal! Use the information below to find the missing measure such that ABC ~ DEF.
AB = 35, DE = 14, DF = 22, m<A = m<D = 57, AC = ?
A. 27
B. 43
C. 55
D. 70
anonymous
 one year ago
Will give medal! Use the information below to find the missing measure such that ABC ~ DEF. AB = 35, DE = 14, DF = 22, m<A = m<D = 57, AC = ? A. 27 B. 43 C. 55 D. 70

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johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So i'm assuming it would just look like dw:1434033084873:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Since we want these to be similar...the length of the first object would just be a factor of the second one So Length AB = Something * Length DE Length AC = Same Something * Length DF Our job is to find out what that "something" is

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Ultimately yes, but for now we need to find out what the "something" is as I have described above \[\large AB = xDE \] \[\large 35 = x(14)\] what is 'x' there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0will it be a decimal?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1It will be yes 35 divided by 14 is a decimal number

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Right....so that means for the lengths AB and DE......AB is 2.5 times bigger than DE Which is what we need because since these are to be "similar" that means the other sides will be subject to the same factor That means that AC would ALSO be 2.5 times bigger than DF...so what would AC be?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well...22 but yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got the answer 55?
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