anonymous
  • anonymous
Will give medal! Use the information below to find the missing measure such that ABC ~ DEF. AB = 35, DE = 14, DF = 22, m
Mathematics
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johnweldon1993
  • johnweldon1993
So i'm assuming it would just look like |dw:1434033084873:dw|
johnweldon1993
  • johnweldon1993
Since we want these to be similar...the length of the first object would just be a factor of the second one So Length AB = Something * Length DE Length AC = Same Something * Length DF Our job is to find out what that "something" is
anonymous
  • anonymous
to find what AC is

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johnweldon1993
  • johnweldon1993
Ultimately yes, but for now we need to find out what the "something" is as I have described above \[\large AB = xDE \] \[\large 35 = x(14)\] what is 'x' there?
anonymous
  • anonymous
will it be a decimal?
johnweldon1993
  • johnweldon1993
It will be yes 35 divided by 14 is a decimal number
anonymous
  • anonymous
2.5
johnweldon1993
  • johnweldon1993
Right....so that means for the lengths AB and DE......AB is 2.5 times bigger than DE Which is what we need because since these are to be "similar" that means the other sides will be subject to the same factor That means that AC would ALSO be 2.5 times bigger than DF...so what would AC be?
anonymous
  • anonymous
Multiply 2.5 x 2?
johnweldon1993
  • johnweldon1993
Well...22 but yes
anonymous
  • anonymous
I got the answer 55?
johnweldon1993
  • johnweldon1993
Correct! :)
anonymous
  • anonymous
ty

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