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donnie1999

  • one year ago

HELLP MEEE PLEASEE!!!!! find the slope and the y-intercept of the equation y-3(x-1)=0

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  1. johnweldon1993
    • one year ago
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    The slope-intercept form of a line is \[\large y =mx + b\] So we need to make our expression look like that \[\large y - 3(x - 1) = 0\] Where would be start?

  2. donnie1999
    • one year ago
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    find what x is equal to I guess

  3. johnweldon1993
    • one year ago
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    Not nearly as complicated, all we need to do is rearrange our equation so that y = something since y = mx + b is the form we want So from \[\large y-3(x-1) = 0\] the first step would be to distribute that 3 into the parenthesis...we want to simplify this a bit

  4. donnie1999
    • one year ago
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    so it would be 3x-3

  5. johnweldon1993
    • one year ago
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    Well yes it could be...normally we would distribute the minus sign with it but that's okay..but we have to make sure that now we have \[\large y - (3x - 3) = 0\] right? What would be next...remember we want y = ...

  6. donnie1999
    • one year ago
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    so do I multiply 0*3x or 0*3

  7. johnweldon1993
    • one year ago
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    No we dont need to multiply at all here \[\large y - (3x - 3) = 0\] If the only thing stopping us from having that y = something is a \(\large -(3x - 3)\) then all we have to do is add it to the other side \[\large y \cancel{- (3x - 3) + (3x - 3)} = 0 + (3x - 3)\] \[\large y = ?\]

  8. donnie1999
    • one year ago
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    so y=-3 srry im kind of clueless

  9. johnweldon1993
    • one year ago
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    No dont worry about it algebra is always tricky in the beginning, actually depending on what you just asked then you're right or wrong lol Well....if we have \(\large y = 0 + (3x - 3)\) that just means we have \[\large y = 3x - 3\] right? So the slope would be? the y-intercept would be?

  10. donnie1999
    • one year ago
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    ok so the slope would be 3 and the y-intercept is -3

  11. johnweldon1993
    • one year ago
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    Perfect!

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