anonymous
  • anonymous
Help with a math problem?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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alekos
  • alekos
the tangent line occurs at the vertex of the this particular function which happens to be a parabola
anonymous
  • anonymous
Okay so first I would have to derive my equation right?
johnweldon1993
  • johnweldon1993
Correct^

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anonymous
  • anonymous
So I would get 9x-3 and then what would I do?
johnweldon1993
  • johnweldon1993
Well from there...you want a tangent line that is horizontal...and since a tangent line is the slope at any given point...that would mean the slope would be 0 right? So if we have the derivative of the function...we need to find where the derivative = 0
anonymous
  • anonymous
So it would be -3 at 0
johnweldon1993
  • johnweldon1993
No I mean we have the derivative...and we want the derivative to equal 0 \[\large 9x - 3 = 0\] solve for 'x' :)
anonymous
  • anonymous
Oh my bad to it would be 3/9.
johnweldon1993
  • johnweldon1993
Mmhmm...or 1/3 right :P So that means that at x = 1/3 ...we will have a horizontal tangent line
anonymous
  • anonymous
And if I wanted to find the equation for the tangent line at 2 would i just plug in 2 into my derived equation?
johnweldon1993
  • johnweldon1993
But we probably should figure out where that will be in terms of 'y' now... So plug in your x = 1/3 into your original equation and solve for 'y'
anonymous
  • anonymous
I got 1.5
johnweldon1993
  • johnweldon1993
Good...so just to finish up the first question At (1/3 , 1.5) there will be a horizontal tangent line
johnweldon1993
  • johnweldon1993
And as far as your second question...yes you would just plug in x = 2 and solve for y in your derived ezpression
johnweldon1993
  • johnweldon1993
Cant spell apparently >.< "expression"
anonymous
  • anonymous
Okay thank you so much!
johnweldon1993
  • johnweldon1993
No problem! :)

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