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anonymous

  • one year ago

Complete the equation of the linear function. Y=_______X+_______

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  1. anonymous
    • one year ago
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    The equation y=mx+c intersects the y-axis at y=c and has a gradient of m. You can either determine this by looking at the graph and seeing how far the line moves per unit in the x-direction, or you can try particular x. e.g. When x=0, y=c and when x=1, y=m+c. Comparing with points on the graph give m and c.

  2. anonymous
    • one year ago
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    ok so im really bad at graphs could you kinda walk me through it

  3. anonymous
    • one year ago
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    Sure. So do you know that for a line y=mx+c, m is the gradient of the line and c is the y-intercept of the line?

  4. anonymous
    • one year ago
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    yeah

  5. anonymous
    • one year ago
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    So if you look at the graph, you know that c is equal to the value of y when the line intersects the y-axis. In other words, it's the value when x=0. Can you say what that is from the diagram?

  6. anonymous
    • one year ago
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    no this is usually where i get lost

  7. anonymous
    • one year ago
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    So the y-axis is the vertical line in the middle of the graph. Do you see where the line you're given crosses it?

  8. anonymous
    • one year ago
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    yeah

  9. anonymous
    • one year ago
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    What is the value of y at that point?

  10. anonymous
    • one year ago
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    1?

  11. anonymous
    • one year ago
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    Yep. So that's your y-intercept, so now we know the line looks like y=mx+1. Now all we need to do is to find m.

  12. anonymous
    • one year ago
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    Do you know how to find the gradient of the line?

  13. anonymous
    • one year ago
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    no

  14. anonymous
    • one year ago
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    Okay. So the gradient (which is m) is essentially how much the line moves up/down when you go to the right by one square (unit). Can you tell what this is from the graph?

  15. anonymous
    • one year ago
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    4?

  16. anonymous
    • one year ago
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    How did you get that?

  17. anonymous
    • one year ago
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    i moved 1 unit to the right then looked how may units it when't up/down. Im guessing i did that wrong

  18. anonymous
    • one year ago
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    The actual gradient is -2 because moving to the right by 1 unit moves the line down by 2 units, can you see this?

  19. anonymous
    • one year ago
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    yeah

  20. anonymous
    • one year ago
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    So then can you write the equation of the line given what we've found out?

  21. anonymous
    • one year ago
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    Y=1X+-2

  22. anonymous
    • one year ago
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    Not quite, you got the y-intercept and the gradient mixed up.

  23. anonymous
    • one year ago
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    The equation of a line is y=(gradient)x +(y-intercept), which you'll often see as y=mx+c.

  24. anonymous
    • one year ago
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    ok so the right way is Y=-2x+1

  25. anonymous
    • one year ago
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    Yes :) Do you think you could apply this method to other questions like this now?

  26. anonymous
    • one year ago
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    yeah

  27. anonymous
    • one year ago
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    Cool :) if you have any problems don't hesitate to ask!

  28. anonymous
    • one year ago
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    k

  29. anonymous
    • one year ago
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    When is the function constant? X=_____to X=_____

  30. anonymous
    • one year ago
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    A constant function is represented as a horizontal line on a graph.

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