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anonymous
 one year ago
Complete the equation of the linear function.
Y=_______X+_______
anonymous
 one year ago
Complete the equation of the linear function. Y=_______X+_______

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation y=mx+c intersects the yaxis at y=c and has a gradient of m. You can either determine this by looking at the graph and seeing how far the line moves per unit in the xdirection, or you can try particular x. e.g. When x=0, y=c and when x=1, y=m+c. Comparing with points on the graph give m and c.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so im really bad at graphs could you kinda walk me through it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sure. So do you know that for a line y=mx+c, m is the gradient of the line and c is the yintercept of the line?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So if you look at the graph, you know that c is equal to the value of y when the line intersects the yaxis. In other words, it's the value when x=0. Can you say what that is from the diagram?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no this is usually where i get lost

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the yaxis is the vertical line in the middle of the graph. Do you see where the line you're given crosses it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the value of y at that point?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep. So that's your yintercept, so now we know the line looks like y=mx+1. Now all we need to do is to find m.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to find the gradient of the line?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. So the gradient (which is m) is essentially how much the line moves up/down when you go to the right by one square (unit). Can you tell what this is from the graph?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you get that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i moved 1 unit to the right then looked how may units it when't up/down. Im guessing i did that wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The actual gradient is 2 because moving to the right by 1 unit moves the line down by 2 units, can you see this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So then can you write the equation of the line given what we've found out?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not quite, you got the yintercept and the gradient mixed up.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation of a line is y=(gradient)x +(yintercept), which you'll often see as y=mx+c.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so the right way is Y=2x+1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes :) Do you think you could apply this method to other questions like this now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Cool :) if you have any problems don't hesitate to ask!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When is the function constant? X=_____to X=_____

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A constant function is represented as a horizontal line on a graph.
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