anonymous
  • anonymous
Complete the equation of the linear function. Y=_______X+_______
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
http://static.k12.com/calms_media/media/1524000_1524500/1524412/1/4ca0974cc0b94f0ca087c628d4c99d7f088b0730/MS_IMC-140901-106145.jpg
anonymous
  • anonymous
The equation y=mx+c intersects the y-axis at y=c and has a gradient of m. You can either determine this by looking at the graph and seeing how far the line moves per unit in the x-direction, or you can try particular x. e.g. When x=0, y=c and when x=1, y=m+c. Comparing with points on the graph give m and c.
anonymous
  • anonymous
ok so im really bad at graphs could you kinda walk me through it

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anonymous
  • anonymous
Sure. So do you know that for a line y=mx+c, m is the gradient of the line and c is the y-intercept of the line?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
So if you look at the graph, you know that c is equal to the value of y when the line intersects the y-axis. In other words, it's the value when x=0. Can you say what that is from the diagram?
anonymous
  • anonymous
no this is usually where i get lost
anonymous
  • anonymous
So the y-axis is the vertical line in the middle of the graph. Do you see where the line you're given crosses it?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
What is the value of y at that point?
anonymous
  • anonymous
1?
anonymous
  • anonymous
Yep. So that's your y-intercept, so now we know the line looks like y=mx+1. Now all we need to do is to find m.
anonymous
  • anonymous
Do you know how to find the gradient of the line?
anonymous
  • anonymous
no
anonymous
  • anonymous
Okay. So the gradient (which is m) is essentially how much the line moves up/down when you go to the right by one square (unit). Can you tell what this is from the graph?
anonymous
  • anonymous
4?
anonymous
  • anonymous
How did you get that?
anonymous
  • anonymous
i moved 1 unit to the right then looked how may units it when't up/down. Im guessing i did that wrong
anonymous
  • anonymous
The actual gradient is -2 because moving to the right by 1 unit moves the line down by 2 units, can you see this?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
So then can you write the equation of the line given what we've found out?
anonymous
  • anonymous
Y=1X+-2
anonymous
  • anonymous
Not quite, you got the y-intercept and the gradient mixed up.
anonymous
  • anonymous
The equation of a line is y=(gradient)x +(y-intercept), which you'll often see as y=mx+c.
anonymous
  • anonymous
ok so the right way is Y=-2x+1
anonymous
  • anonymous
Yes :) Do you think you could apply this method to other questions like this now?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
Cool :) if you have any problems don't hesitate to ask!
anonymous
  • anonymous
k
anonymous
  • anonymous
When is the function constant? X=_____to X=_____
anonymous
  • anonymous
http://static.k12.com/calms_media/media/1524000_1524500/1524416/1/411ba68c64d77faa64f19231dbddc8c7ba7e16fa/MS_IMC-140901-106149.jpg
anonymous
  • anonymous
A constant function is represented as a horizontal line on a graph.

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