anonymous
  • anonymous
Someone please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
With what?
anonymous
  • anonymous
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anonymous
  • anonymous
Just wondering are you in connections?

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anonymous
  • anonymous
Yes I am
anonymous
  • anonymous
I am as well. I had trouble on a question like this ask @johnweldon1993 he'll probably be more help here.
anonymous
  • anonymous
thanks
johnweldon1993
  • johnweldon1993
So we first start with the restrictions...they can come up at ANY point of our simplification process.. So restrictions here would be whatever 'x' values make the denominator = 0 (in either fraction) what would those be?
johnweldon1993
  • johnweldon1993
Hint would be to factor the denominators :)
anonymous
  • anonymous
oh ok give me a sec
anonymous
  • anonymous
ok so the first one factored would be (x+4)(x-1) and I have to find what x would be to make this equal 0?
johnweldon1993
  • johnweldon1993
Correct
anonymous
  • anonymous
it would be -4 and 1
johnweldon1993
  • johnweldon1993
Okay great...2 restrictions down so far But...what about the other fraction now?
anonymous
  • anonymous
so you said I just have to do it for the denominator?
johnweldon1993
  • johnweldon1993
mmhmm, we know dividing anything by 0 makes for an undefined answer...so whenever denominators = 0 we have a restriction
anonymous
  • anonymous
alright so for this one it would be -4 and -1
johnweldon1993
  • johnweldon1993
That is correct...and yet I dont see any answer choices with a -1 as a restriction...odd...but oh well, aybe they just missed one Okay so now we begin to simplify...how would we begin?
anonymous
  • anonymous
none of my answer look right with this... are you sure this is how you do it?
anonymous
  • anonymous
the restrictions should be -4, 1, -1 but those aren't in any answers
johnweldon1993
  • johnweldon1993
Yup. Find restrictions...then simplify..and I know thats why I was confused as to why the -1 wasnt there And we also will have more restrictions in a little bit
anonymous
  • anonymous
ok well how do I start to simplify?
johnweldon1993
  • johnweldon1993
Well the first thing I would do....is turn this into multiplication...we would do that by flipping the second fraction \[\large \frac{5-x}{x^2 + 3x - 4} \times \frac{x^2 + 5x + 4}{x^2 - 2x - 15}\] make sense?
anonymous
  • anonymous
\[\frac{ 5-x }{ (x+4)(x-1) } \ \times \frac{ (x+4)(x+1) }{ (x+3)(x-5) } \]
anonymous
  • anonymous
so like this?
johnweldon1993
  • johnweldon1993
Perfect...and NOW we simplified...we need to check for any more restrictions!!
anonymous
  • anonymous
ok so -3 and 5?
johnweldon1993
  • johnweldon1993
Right...so literally in total...we SHOULD have 5 restrictions on the problem...but they only give us 4
anonymous
  • anonymous
huh ok
anonymous
  • anonymous
so its B?
johnweldon1993
  • johnweldon1993
It would be ye...you simplified and got that right?
anonymous
  • anonymous
well its the only one with the correct restrictions. and yes I simplified to the point of knowing it couldn't be the other ones
anonymous
  • anonymous
thank you so much ^.^ a medal and a hug for you *hug* lol
johnweldon1993
  • johnweldon1993
Well thank you but the hug was the best part! :P lol
anonymous
  • anonymous
haha well you're honestly the first I've ever given a hug for helping me :P ^.^
johnweldon1993
  • johnweldon1993
Woo! I get the special hug!!! lol :P I'll treasure it always haha
anonymous
  • anonymous
haha good xD

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