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anonymous

  • one year ago

Someone please help!

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  1. anonymous
    • one year ago
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    With what?

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    Just wondering are you in connections?

  4. anonymous
    • one year ago
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    Yes I am

  5. anonymous
    • one year ago
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    I am as well. I had trouble on a question like this ask @johnweldon1993 he'll probably be more help here.

  6. anonymous
    • one year ago
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    thanks

  7. johnweldon1993
    • one year ago
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    So we first start with the restrictions...they can come up at ANY point of our simplification process.. So restrictions here would be whatever 'x' values make the denominator = 0 (in either fraction) what would those be?

  8. johnweldon1993
    • one year ago
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    Hint would be to factor the denominators :)

  9. anonymous
    • one year ago
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    oh ok give me a sec

  10. anonymous
    • one year ago
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    ok so the first one factored would be (x+4)(x-1) and I have to find what x would be to make this equal 0?

  11. johnweldon1993
    • one year ago
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    Correct

  12. anonymous
    • one year ago
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    it would be -4 and 1

  13. johnweldon1993
    • one year ago
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    Okay great...2 restrictions down so far But...what about the other fraction now?

  14. anonymous
    • one year ago
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    so you said I just have to do it for the denominator?

  15. johnweldon1993
    • one year ago
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    mmhmm, we know dividing anything by 0 makes for an undefined answer...so whenever denominators = 0 we have a restriction

  16. anonymous
    • one year ago
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    alright so for this one it would be -4 and -1

  17. johnweldon1993
    • one year ago
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    That is correct...and yet I dont see any answer choices with a -1 as a restriction...odd...but oh well, aybe they just missed one Okay so now we begin to simplify...how would we begin?

  18. anonymous
    • one year ago
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    none of my answer look right with this... are you sure this is how you do it?

  19. anonymous
    • one year ago
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    the restrictions should be -4, 1, -1 but those aren't in any answers

  20. johnweldon1993
    • one year ago
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    Yup. Find restrictions...then simplify..and I know thats why I was confused as to why the -1 wasnt there And we also will have more restrictions in a little bit

  21. anonymous
    • one year ago
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    ok well how do I start to simplify?

  22. johnweldon1993
    • one year ago
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    Well the first thing I would do....is turn this into multiplication...we would do that by flipping the second fraction \[\large \frac{5-x}{x^2 + 3x - 4} \times \frac{x^2 + 5x + 4}{x^2 - 2x - 15}\] make sense?

  23. anonymous
    • one year ago
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    \[\frac{ 5-x }{ (x+4)(x-1) } \ \times \frac{ (x+4)(x+1) }{ (x+3)(x-5) } \]

  24. anonymous
    • one year ago
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    so like this?

  25. johnweldon1993
    • one year ago
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    Perfect...and NOW we simplified...we need to check for any more restrictions!!

  26. anonymous
    • one year ago
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    ok so -3 and 5?

  27. johnweldon1993
    • one year ago
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    Right...so literally in total...we SHOULD have 5 restrictions on the problem...but they only give us 4

  28. anonymous
    • one year ago
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    huh ok

  29. anonymous
    • one year ago
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    so its B?

  30. johnweldon1993
    • one year ago
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    It would be ye...you simplified and got that right?

  31. anonymous
    • one year ago
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    well its the only one with the correct restrictions. and yes I simplified to the point of knowing it couldn't be the other ones

  32. anonymous
    • one year ago
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    thank you so much ^.^ a medal and a hug for you *hug* lol

  33. johnweldon1993
    • one year ago
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    Well thank you but the hug was the best part! :P lol

  34. anonymous
    • one year ago
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    haha well you're honestly the first I've ever given a hug for helping me :P ^.^

  35. johnweldon1993
    • one year ago
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    Woo! I get the special hug!!! lol :P I'll treasure it always haha

  36. anonymous
    • one year ago
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    haha good xD

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