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anonymous
 one year ago
Someone please help!
anonymous
 one year ago
Someone please help!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just wondering are you in connections?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am as well. I had trouble on a question like this ask @johnweldon1993 he'll probably be more help here.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So we first start with the restrictions...they can come up at ANY point of our simplification process.. So restrictions here would be whatever 'x' values make the denominator = 0 (in either fraction) what would those be?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Hint would be to factor the denominators :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so the first one factored would be (x+4)(x1) and I have to find what x would be to make this equal 0?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it would be 4 and 1

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Okay great...2 restrictions down so far But...what about the other fraction now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you said I just have to do it for the denominator?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1mmhmm, we know dividing anything by 0 makes for an undefined answer...so whenever denominators = 0 we have a restriction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright so for this one it would be 4 and 1

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1That is correct...and yet I dont see any answer choices with a 1 as a restriction...odd...but oh well, aybe they just missed one Okay so now we begin to simplify...how would we begin?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0none of my answer look right with this... are you sure this is how you do it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the restrictions should be 4, 1, 1 but those aren't in any answers

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Yup. Find restrictions...then simplify..and I know thats why I was confused as to why the 1 wasnt there And we also will have more restrictions in a little bit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok well how do I start to simplify?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well the first thing I would do....is turn this into multiplication...we would do that by flipping the second fraction \[\large \frac{5x}{x^2 + 3x  4} \times \frac{x^2 + 5x + 4}{x^2  2x  15}\] make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 5x }{ (x+4)(x1) } \ \times \frac{ (x+4)(x+1) }{ (x+3)(x5) } \]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Perfect...and NOW we simplified...we need to check for any more restrictions!!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Right...so literally in total...we SHOULD have 5 restrictions on the problem...but they only give us 4

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1It would be ye...you simplified and got that right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well its the only one with the correct restrictions. and yes I simplified to the point of knowing it couldn't be the other ones

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much ^.^ a medal and a hug for you *hug* lol

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well thank you but the hug was the best part! :P lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha well you're honestly the first I've ever given a hug for helping me :P ^.^

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Woo! I get the special hug!!! lol :P I'll treasure it always haha
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