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anonymous
 one year ago
FAN AND MEDAL!!!
Solve for x.
ax + 2b > 8
A) x < the quantity negative 2 times b plus 8 all over negative a
B) x > the quantity negative 2 times b plus 8 all over negative a
C) x < the quantity 2 times b minus 8 all over negative a
D) x > the quantity negative 2 times b minus 8 all over a
anonymous
 one year ago
FAN AND MEDAL!!! Solve for x. ax + 2b > 8 A) x < the quantity negative 2 times b plus 8 all over negative a B) x > the quantity negative 2 times b plus 8 all over negative a C) x < the quantity 2 times b minus 8 all over negative a D) x > the quantity negative 2 times b minus 8 all over a

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0treat the > as an = and solve for x first then put the > back in.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but there are 2 variables

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it doesn't matter as you are only solving for x. You treat the other variable b as a constant.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you arrive to that answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ax + 2b > 8 Subtract 2b from both sides ax > 8  2b Divide both sides by a and switch the > sign to < x < 8  2b all over a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why would you switch the signs?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have to switch the sign when you divide by a negative
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