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anonymous

  • one year ago

FAN AND MEDAL!!! Solve for x. -ax + 2b > 8 A) x < the quantity negative 2 times b plus 8 all over negative a B) x > the quantity negative 2 times b plus 8 all over negative a C) x < the quantity 2 times b minus 8 all over negative a D) x > the quantity negative 2 times b minus 8 all over a

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  1. Rhystic
    • one year ago
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    treat the > as an = and solve for x first then put the > back in.

  2. anonymous
    • one year ago
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    but there are 2 variables

  3. Rhystic
    • one year ago
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    it doesn't matter as you are only solving for x. You treat the other variable b as a constant.

  4. anonymous
    • one year ago
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    So it's A?

  5. Rhystic
    • one year ago
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    how did you arrive to that answer?

  6. anonymous
    • one year ago
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    -ax + 2b > 8 Subtract 2b from both sides -ax > 8 - 2b Divide both sides by -a and switch the > sign to < x < 8 - 2b all over -a

  7. anonymous
    • one year ago
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    So it's A?

  8. Rhystic
    • one year ago
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    why would you switch the signs?

  9. anonymous
    • one year ago
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    You have to switch the sign when you divide by a negative

  10. anonymous
    • one year ago
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    So it's A, right?

  11. Rhystic
    • one year ago
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    yep

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