FAN AND MEDAL

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Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6). Choose one answer. a. y = one thirdx + 7 b. y = −3x + 3 c. y = one thirdx + 3 d. y = −3x + 7
The gradient is equal to -3 since they are parallel.
You are given a coordinate of a point where the line passes. So any idea?

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Hmm What would my first step be?
Pretty confused with this
|dw:1434038614067:dw|
m - gradient c - intercept
ok youre first step would be to look at the slope/gradient. the standard formula for a straight line is y = mx +b where m is the slope/gradient. For a straight line to be parallel to another the two lines must have the same slope. In this case you are looking for a slope of -3 or something in the form of y = -3x +b. That means two of the answers are completely wrong. the next step is to take the point given (-1,6) (x,y) and plug them in to corresponding x and y values in the equation the remaining answers and see if they work meaning if you plug in -1 for x into the equation do you come out with 6 for the y value.
ok so it would be b or d?
@Rhystic Nicely explained. :)
@kyle55 Plug a value and check whether you get 6 for y.
whts the equation?
y= -3x + 3?
Try both of them (b and d). Plug -1 for x and see whether you get 6 for y. If it does it's the equation. :)
Correct!
6= -3(-1) + 3 ?
yeah
6=4 + 3 so that is not the answer?
That's the equation of the line parallel to y=-3x+12
-3 * -1 = +3
Not sure i understand quite yet
Am I wrong @Aureyliant ? :)
Everything looks correct… Although not sure because I didn't check the overall problem's answer.
@Aureyliant Can you explain it to kyle?
Kyle what part didn't you understand?
I got lost somewhere in the middle. Can you start from the beggining and work it out for me?
y = mx+c is the general form of a straight line equation where m is the gradient of the line and c is the intercept.
|dw:1434039972898:dw|
You are given the coordinates of a point where the new line should pass.
alright
then we plug the options in?
Since the gradient is equal to -3 there are two answers (b and d). The line should also go through the point (-1,6). So if we plug x=-1 for one of the two equations, the one that gets y=6 is the answer.
so b. y = −3x + 3
i plug -1 into x and 6 into y ?
You don't plug in a value for y. You need to only substitute -1 for x. If you get y=6 for the answer, then that's equation of the line satisfying the above conditions.
thats what i was confused wit i thinkh
so b is the answer
no you just use the x value and see what number comes out for y if that number matches the y coordinate that you are given then it is correct. for example in this case the correct answer is b. you are given y = -3x +3 and coordinate (-1,6) you use the x value (-1) in the equation: y= -3*-1+3 and see if you get 6 if you do then that equation has a line passing through the coordinate you need.
thank you for the help
Did you understand it?
Yes, i was confused about where to plug everything in. Should i ask another question to make sure i got it?
Ok go ahead. :)
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3). Choose one answer. a. y = 2x + 6 b. y = −one halfx + 3 c. y = −one halfx + 6 d. y = 2x + 3
Try doing it in another thread so others have the chance to gain medals.
oh i will sorry
No problem! :)

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