anonymous
  • anonymous
evaluate this expression when s=7, a=5, m=3, and t=4
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1434039934968:dw|
anonymous
  • anonymous
Basically substitute those numbers for your variables in the equation
anonymous
  • anonymous
Try plugging in the numbers yourself :)

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anonymous
  • anonymous
I got 137
anonymous
  • anonymous
|dw:1434040152742:dw|
anonymous
  • anonymous
|dw:1434040218159:dw|
anonymous
  • anonymous
Try again :)
anonymous
  • anonymous
s=7, a=5, m=3, and t=4 \[2a ^{2} + st -3m = 2(5)^{2} + (7)(4) -3(3) = 69\]
anonymous
  • anonymous
I got 119
anonymous
  • anonymous
119
anonymous
  • anonymous
Simply plug it into your calculator and you should get the right answer
anonymous
  • anonymous
@happyrosy It should be 10^2
anonymous
  • anonymous
(2a)^2 (2 times 5)^2 10^2
anonymous
  • anonymous
100
anonymous
  • anonymous
So 100 + 28 - 9 = 119
anonymous
  • anonymous
No it is actually 2(5)^2 = 50
anonymous
  • anonymous
Use the calculator. You'll get that answer
anonymous
  • anonymous
lol yall are confusing me
anonymous
  • anonymous
The 2a is in parenthesis… they must be multiplied first.
anonymous
  • anonymous
You should put parenthesis around whatever you do in the calculator
anonymous
  • anonymous
You have to solve 5^2 first in 2(5)^2 = 2(25) = 50
anonymous
  • anonymous
@Wolverine32 We need a neutral person
anonymous
  • anonymous
2a isn't in parenthesis. Just a is. So focus on the 5 first and then go for the exponent, which is 2. 5 squared = 25. Multiply that by 2 you get 50
anonymous
  • anonymous
http://prntscr.com/7fsczz 2a is in parenthesis.
anonymous
  • anonymous
so is it like this 2(5)^2+7(4)-3(3)
anonymous
  • anonymous
You gave the problem like (2*5)^2 + 28 - 9
anonymous
  • anonymous
simply put the number to the alphbet (2a)^2+st-3m s=7 a= 5 m=3 t= 4 y=2^x-1 it should look like this know put it in ur ti 84 calutor (2*5)^2+7*4-3*3.
anonymous
  • anonymous
^ Precisely.
anonymous
  • anonymous
the answer is going to be119
anonymous
  • anonymous
Yes :)
anonymous
  • anonymous
Oh okay. So it is actually \[(2a)^2\] not \[2a^2\]
anonymous
  • anonymous
great job
anonymous
  • anonymous
Sorry for the confusion. Lol! XD

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