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billyjean

  • one year ago

ABC has side lengths 20,24, and 31. Do the side lengths form a Pythagorean triple?

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  1. anonymous
    • one year ago
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    Does A^2 + B^2 = C^2?

  2. billyjean
    • one year ago
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    yes

  3. Here_to_Help15
    • one year ago
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    \( 20^2 * 24^2= 31^2 ? \)

  4. mathmath333
    • one year ago
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    here \(C>B,A\)

  5. anonymous
    • one year ago
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    Then t forms a triple

  6. Here_to_Help15
    • one year ago
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    So 20 * 20 =400 and 24*24= 576

  7. anonymous
    • one year ago
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    But A^2 + B^2 does not equal C^2

  8. mathmath333
    • one year ago
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    it should be this \(20^2 \color{red}{+} 24^2= 31^2 ?\)

  9. Here_to_Help15
    • one year ago
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    \(576+400= 976\)

  10. billyjean
    • one year ago
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    the answer choices are yes or no

  11. Here_to_Help15
    • one year ago
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    Oops didnt see that thanks @mathmath333

  12. Here_to_Help15
    • one year ago
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    Ok so \(A^2+B^2 = 976 \) does C^2 = 976 ? If not then it is no.

  13. Here_to_Help15
    • one year ago
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    So does \(31*31=976\) ?

  14. Here_to_Help15
    • one year ago
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    @billyjean ?

  15. billyjean
    • one year ago
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    yes it equals to 976

  16. Here_to_Help15
    • one year ago
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    No no no it does not lets multiply it again and see what it turns out to be.

  17. Here_to_Help15
    • one year ago
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    |dw:1434048037034:dw|

  18. Here_to_Help15
    • one year ago
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    Since it equals 961 that means its ..... yes or no?

  19. Here_to_Help15
    • one year ago
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    Yes it means No

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