anonymous
  • anonymous
Please help! 1. How many valence electrons are in the outermost energy level of each of the following elements? a. Helium b. Lithium c. Nitrogen d. Magnesium I listed them as letters to make it easier to understand...
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Abhisar
  • Abhisar
Do you know how to write electronic configurations?
anonymous
  • anonymous
?electronic configurations?
Abhisar
  • Abhisar
Yes, like for helium (atomic number 2) we write \(\sf 1s^2\)

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Abhisar
  • Abhisar
For nitrogen (atomic number 7) we write \(\sf 1s^2 2s^2 2p^3\)
Abhisar
  • Abhisar
any idea?
anonymous
  • anonymous
nope... no clue, sorry I am literally so stupid when it comes to all this electron atom stuff.
Abhisar
  • Abhisar
Then how will you solve this?
anonymous
  • anonymous
I am trying to understand it, so let me think out loud here
anonymous
  • anonymous
would you solve it like an equation? @Abhisar
Abhisar
  • Abhisar
Good, I may teach you a short trick but it may not be always correct but you will just do fine for school level.
anonymous
  • anonymous
ok... I will start with helium. 1s^2. first would you find the square root of 1s?
Abhisar
  • Abhisar
No it's not square (-: It means there are 2 electrons in 1s orbital.
anonymous
  • anonymous
ohhhk
Abhisar
  • Abhisar
Leave it, just remember the sequence 2, 8, 8, 18
Abhisar
  • Abhisar
Now, if i say you to write the configuration of nitrogen (atomic no 7). You will write 2, 5 (Why five? because the sum has to be 7)
Abhisar
  • Abhisar
Getting?
anonymous
  • anonymous
ok I am following you
Abhisar
  • Abhisar
So, if i say write for lithium (atomic no. 3), how will ya do?
anonymous
  • anonymous
I would write 1, 2?
Abhisar
  • Abhisar
2, 1
Abhisar
  • Abhisar
Remember the series. It's 2, 8, 8, 18
Abhisar
  • Abhisar
ok?
anonymous
  • anonymous
ok I get it
Abhisar
  • Abhisar
For Magnesium (12)
anonymous
  • anonymous
8, 4?
Abhisar
  • Abhisar
Nopes.
anonymous
  • anonymous
6, 6
Abhisar
  • Abhisar
See the series, 2, 8, 8, 18 So will write first 2, now we need 10 more. So next we write 2, 8, now we need 2 more so finally we write 2, 8, 2. Got it now?
anonymous
  • anonymous
yehh
Abhisar
  • Abhisar
Finally write for hydrogen
Abhisar
  • Abhisar
sorry , for helium
Abhisar
  • Abhisar
attomic number is 2
anonymous
  • anonymous
wouldnt it just be 2?
Abhisar
  • Abhisar
Correct !!!
anonymous
  • anonymous
so I have the numbers: a. Helium- 2 b. Lithium-2,1 c. Nitrogen-2,5 d. Magnesium-2,8,2
Abhisar
  • Abhisar
Well done! Now we know that electronic configurations for the given elements are as following a. Helium = 2 b. Lithium = 2, 1 c. Nitrogen = 2,5 d. Magnesium = 2,8,2 How to calculate valence electron now??? The last number in each of them represents the valence electrons. So for nitrogen, number of valence electrons will be 2.
anonymous
  • anonymous
huh?
Abhisar
  • Abhisar
Can you tell me the number of valence electrons for the rest?
anonymous
  • anonymous
if it's the last number, wait what is that referring to ?
anonymous
  • anonymous
what placement is it referring to?
Abhisar
  • Abhisar
I am not able to understand ur question..
anonymous
  • anonymous
what do you mean by "The last number in each of them represents the valence electrons." ^^^^^^^^^^^^
Abhisar
  • Abhisar
|dw:1434048894292:dw|
anonymous
  • anonymous
yes but you said that 2 was nitrogen's number, but wouldnt it be 5?
Abhisar
  • Abhisar
When did I say that? Yes, nitrogen has 5 valence electrons.
anonymous
  • anonymous
XD "The last number in each of them represents the valence electrons. So for nitrogen, number of valence electrons will be 2."
Abhisar
  • Abhisar
Last is 5 :( See, what we wrote for Nitrogen. (2, 5). 2 is first and 5 is last. Getting it?
Abhisar
  • Abhisar
Oh, sorry that was a typo :D
anonymous
  • anonymous
I see! so the numbers would be: a. Helium = 2 b. Lithium = 1 c. Nitrogen = 5 d. Magnesium = 2
Abhisar
  • Abhisar
\(\color{blue}{\text{Originally Posted by}}\) @Abhisar Well done! Now we know that electronic configurations for the given elements are as following a. Helium = 2 b. Lithium = 2, 1 c. Nitrogen = 2,5 d. Magnesium = 2,8,2 How to calculate valence electron now??? The last number in each of them represents the valence electrons. So for nitrogen, number of valence electrons will be 5. \(\color{blue}{\text{End of Quote}}\)
Abhisar
  • Abhisar
Correct!
anonymous
  • anonymous
thank you
Abhisar
  • Abhisar
You're welcome (-:

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