anonymous
  • anonymous
Can someone explain to me how to turn these numbers into a horizontal ellipse and a horizontal hyperbola equation? I'm trying to create their location on the y-axis.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
The problem is phsycially this There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.
anonymous
  • anonymous
The numbers are the focuses, (3, 0) and (-3, 0) The minors or others are (0, 2.5) and (0, -2.5)
amoodarya
  • amoodarya
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amoodarya
  • amoodarya
\[b^2+c^2=a^2\\2.5^2+3^2=a^2\\\frac{(x-0)^2}{a^2}+\frac{(y-0)^2}{b^2}=1\\\frac{(x-0)^2}{2.5^2+3^2}+\frac{(y-0)^2}{2.5^2}=1\]
anonymous
  • anonymous
@amoodarya how would you translate that into text and not that fancy stuff? I need to submit it in a format like 2 + 2 /(divide)/ 2, if that makes sense
amoodarya
  • amoodarya
you can translate it by yourself ,can't you ?
anonymous
  • anonymous
one second,
anonymous
  • anonymous
b^2 + c^2 = a^2 2.5^2 + 3^2 = a^2 (x - 0)^2/a^2 + (y - 0)^2/b^2 = 1 (x - 0^2)^2/2.5^2 + 3^2 (y - 0)^2/2.5^2 = 1 is this how to do that?
amoodarya
  • amoodarya
yes
anonymous
  • anonymous
ok thank you.
anonymous
  • anonymous
sent it for a submission and i got this @amoodarya "Yep, your work has to be right though and your equation as written is not. A and b are not going to be the same and that's what you have. please show the work and include the hyperbola stuff too as it is all part of the same question." I don't really get the whole problem tho, can you help?
anonymous
  • anonymous
would you get rid of the 2.5^2 + 3^2 and make it just 3^2?
anonymous
  • anonymous
"I need to see ALL of your work to find a^2 and your final equation."
anonymous
  • anonymous
is (x^2 - y^2) / 21.5 correct?
anonymous
  • anonymous
@campbell_st

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