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anonymous

  • one year ago

Can someone explain to me how to turn these numbers into a horizontal ellipse and a horizontal hyperbola equation? I'm trying to create their location on the y-axis.

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  1. anonymous
    • one year ago
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    The problem is phsycially this There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.

  2. anonymous
    • one year ago
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    The numbers are the focuses, (3, 0) and (-3, 0) The minors or others are (0, 2.5) and (0, -2.5)

  3. amoodarya
    • one year ago
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    |dw:1434049567436:dw|

  4. amoodarya
    • one year ago
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    \[b^2+c^2=a^2\\2.5^2+3^2=a^2\\\frac{(x-0)^2}{a^2}+\frac{(y-0)^2}{b^2}=1\\\frac{(x-0)^2}{2.5^2+3^2}+\frac{(y-0)^2}{2.5^2}=1\]

  5. anonymous
    • one year ago
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    @amoodarya how would you translate that into text and not that fancy stuff? I need to submit it in a format like 2 + 2 /(divide)/ 2, if that makes sense

  6. amoodarya
    • one year ago
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    you can translate it by yourself ,can't you ?

  7. anonymous
    • one year ago
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    one second,

  8. anonymous
    • one year ago
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    b^2 + c^2 = a^2 2.5^2 + 3^2 = a^2 (x - 0)^2/a^2 + (y - 0)^2/b^2 = 1 (x - 0^2)^2/2.5^2 + 3^2 (y - 0)^2/2.5^2 = 1 is this how to do that?

  9. amoodarya
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    ok thank you.

  11. anonymous
    • one year ago
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    sent it for a submission and i got this @amoodarya "Yep, your work has to be right though and your equation as written is not. A and b are not going to be the same and that's what you have. please show the work and include the hyperbola stuff too as it is all part of the same question." I don't really get the whole problem tho, can you help?

  12. anonymous
    • one year ago
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    would you get rid of the 2.5^2 + 3^2 and make it just 3^2?

  13. anonymous
    • one year ago
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    "I need to see ALL of your work to find a^2 and your final equation."

  14. anonymous
    • one year ago
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    is (x^2 - y^2) / 21.5 correct?

  15. anonymous
    • one year ago
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    @campbell_st

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