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anonymous

  • one year ago

There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane. Can someone please help? I really want to know how to do this but it is hard to understand. I will give a medal!!!

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  1. anonymous
    • one year ago
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    you can graph the equations using desmos

  2. anonymous
    • one year ago
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    thanks for replying. but honestly, Im doing this online and I don't understand anything. I need someone to help me step by step

  3. anonymous
    • one year ago
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    ok

  4. anonymous
    • one year ago
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    are you there?

  5. anonymous
    • one year ago
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    yes im here. give me a second

  6. anonymous
    • one year ago
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    np just making sure

  7. anonymous
    • one year ago
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    okay. what else do I do?

  8. anonymous
    • one year ago
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    does it look like this?

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  9. anonymous
    • one year ago
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    it can't have a zero.... sorry i completely misread your problem, lets start over:

  10. anonymous
    • one year ago
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    the points are focal points, not vertexes, so it won't work

  11. anonymous
    • one year ago
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    okay. sure :)

  12. anonymous
    • one year ago
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    you can use :a^2−b^2=c^2 3,4,5 work to get: a=5,b=4 c=3 and use x^2/5^2+y^2/4^2=1 this graph will make your foci (−3,0) and (3,0)

  13. anonymous
    • one year ago
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  14. anonymous
    • one year ago
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    i just attached the graph

  15. anonymous
    • one year ago
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    for the hyperbola x^2/a^2−y^2/b^2=1 you can use this formula: a^2+b^2=3^3 make a^2=8,b^2=1 to get 9, then plug them in to get: x^2/8−y^2=1

  16. anonymous
    • one year ago
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    x^2/8−y^2=1 this is your hyperbola

  17. anonymous
    • one year ago
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    if you graph the hyperbola, ellipse, and two points, on one graph you will have your answer

  18. anonymous
    • one year ago
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    ooh okay. thanks, ill do it then show you what I have

  19. anonymous
    • one year ago
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    http://www.wolframalpha.com/input/?i=+x^2%2F8-y^2%3D1%2Cx^2%2F25%2By^2%2F16%3D1

  20. anonymous
    • one year ago
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    is what it should look like

  21. anonymous
    • one year ago
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    sorry it took a bit long and i messed up at first

  22. anonymous
    • one year ago
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    thats okay, thanks

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spraguer (Moderator)
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