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you can graph the equations using desmos
thanks for replying. but honestly, Im doing this online and I don't understand anything. I need someone to help me step by step
are you there?
yes im here. give me a second
np just making sure
okay. what else do I do?
it can't have a zero.... sorry i completely misread your problem, lets start over:
the points are focal points, not vertexes, so it won't work
okay. sure :)
you can use :a^2−b^2=c^2 3,4,5 work to get: a=5,b=4 c=3 and use x^2/5^2+y^2/4^2=1 this graph will make your foci (−3,0) and (3,0)
i just attached the graph
for the hyperbola x^2/a^2−y^2/b^2=1 you can use this formula: a^2+b^2=3^3 make a^2=8,b^2=1 to get 9, then plug them in to get: x^2/8−y^2=1
x^2/8−y^2=1 this is your hyperbola
if you graph the hyperbola, ellipse, and two points, on one graph you will have your answer
ooh okay. thanks, ill do it then show you what I have
is what it should look like
sorry it took a bit long and i messed up at first
thats okay, thanks