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anonymous
 one year ago
There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the yaxis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.
Can someone please help? I really want to know how to do this but it is hard to understand. I will give a medal!!!
anonymous
 one year ago
There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the yaxis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane. Can someone please help? I really want to know how to do this but it is hard to understand. I will give a medal!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can graph the equations using desmos

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for replying. but honestly, Im doing this online and I don't understand anything. I need someone to help me step by step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes im here. give me a second

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay. what else do I do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does it look like this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it can't have a zero.... sorry i completely misread your problem, lets start over:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the points are focal points, not vertexes, so it won't work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can use :a^2−b^2=c^2 3,4,5 work to get: a=5,b=4 c=3 and use x^2/5^2+y^2/4^2=1 this graph will make your foci (−3,0) and (3,0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just attached the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the hyperbola x^2/a^2−y^2/b^2=1 you can use this formula: a^2+b^2=3^3 make a^2=8,b^2=1 to get 9, then plug them in to get: x^2/8−y^2=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2/8−y^2=1 this is your hyperbola

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you graph the hyperbola, ellipse, and two points, on one graph you will have your answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooh okay. thanks, ill do it then show you what I have

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=+x^2%2F8y^2%3D1%2Cx^2%2F25%2By^2%2F16%3D1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is what it should look like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry it took a bit long and i messed up at first
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