anonymous
  • anonymous
There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane. Can someone please help? I really want to know how to do this but it is hard to understand. I will give a medal!!!
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
you can graph the equations using desmos
anonymous
  • anonymous
thanks for replying. but honestly, Im doing this online and I don't understand anything. I need someone to help me step by step
anonymous
  • anonymous
ok

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anonymous
  • anonymous
are you there?
anonymous
  • anonymous
yes im here. give me a second
anonymous
  • anonymous
np just making sure
anonymous
  • anonymous
okay. what else do I do?
anonymous
  • anonymous
does it look like this?
1 Attachment
anonymous
  • anonymous
it can't have a zero.... sorry i completely misread your problem, lets start over:
anonymous
  • anonymous
the points are focal points, not vertexes, so it won't work
anonymous
  • anonymous
okay. sure :)
anonymous
  • anonymous
you can use :a^2−b^2=c^2 3,4,5 work to get: a=5,b=4 c=3 and use x^2/5^2+y^2/4^2=1 this graph will make your foci (−3,0) and (3,0)
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
i just attached the graph
anonymous
  • anonymous
for the hyperbola x^2/a^2−y^2/b^2=1 you can use this formula: a^2+b^2=3^3 make a^2=8,b^2=1 to get 9, then plug them in to get: x^2/8−y^2=1
anonymous
  • anonymous
x^2/8−y^2=1 this is your hyperbola
anonymous
  • anonymous
if you graph the hyperbola, ellipse, and two points, on one graph you will have your answer
anonymous
  • anonymous
ooh okay. thanks, ill do it then show you what I have
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=+x^2%2F8-y^2%3D1%2Cx^2%2F25%2By^2%2F16%3D1
anonymous
  • anonymous
is what it should look like
anonymous
  • anonymous
sorry it took a bit long and i messed up at first
anonymous
  • anonymous
thats okay, thanks

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