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Jravenv

  • one year ago

Help me please, Best answer given, Screenshot in the comments.

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  1. Jravenv
    • one year ago
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  2. Owlcoffee
    • one year ago
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    is it like this? \[A=\frac{ k }{ 2(m+n) }\]

  3. Jravenv
    • one year ago
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    We're solving for m

  4. Owlcoffee
    • one year ago
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    Ok, we will begin by stating the equation given: \[A=\frac{ k }{ 2 }(m+n)\] Now, this is what we can call a "parametric equation", why?, because we can see that it has variables that can represent a parameter in the area. When we solve for one of those variables, we treat everything else as if they were constants, meaning, they are just numbers, we don't pay attention to any further theory of them. So, we will begin by multiplying both sides by "" and also dividing by "k": \[(\frac{ 2 }{ k })A=\frac{ k }{ 2 }(m+n)(\frac{ 2 }{ k })\] \[\frac{ 2A }{ k }=(m+n) \] And then sustract "n" to both: \[\frac{ 2A }{ k }-n=m+n-n\] \[\frac{ 2A }{ k }-n=m\] By the conmmutative property of the number we can turn it around: \[m=\frac{ 2A }{ k }-n\] And simplifying that fraction: \[m=\frac{ 2A-kn }{ k }\]

  5. Jravenv
    • one year ago
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    Ohh thank you very much! that makes sense, thanks for not just giving me the answer.

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