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anonymous

  • one year ago

Mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $25 to buy a total of 20 packets of wafers of the two varieties. Part A: Write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that Mike and his friends bought at the carnival. Define the variables used in the equations. Part B: How many packets of chocolate wafers and cheese wafers did they buy?Explain how you got the answer and why you selected a particular me

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  1. anonymous
    • one year ago
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    Alright so system of eqations: Lets call the amount of chocolate wafer packets (c) and the amount of cheese wafer packets (h) They bought a total of 20 packets so: c + h = 20 They spent $25 dollars, and chocolate packets were $1 while cheese were $2, so: c(1) + h(2) = 25

  2. anonymous
    • one year ago
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    Do you get it so far?

  3. anonymous
    • one year ago
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    yes!

  4. anonymous
    • one year ago
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    Alright awesome :) next part, to solve for this, we just use substitution

  5. anonymous
    • one year ago
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    alright

  6. anonymous
    • one year ago
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    I think you should try this one out yourself before I give you any answers :P Hint: Solve for h first by making the first equation into c = bla bla bla

  7. anonymous
    • one year ago
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    5

  8. anonymous
    • one year ago
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    Do you want to show me your steps and how you got there or are you in a bit of a rush to get something done?

  9. anonymous
    • one year ago
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    or 15?...-_-

  10. anonymous
    • one year ago
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    no rush

  11. anonymous
    • one year ago
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    Alright, so show me step by step what you did and I will guide you in the right direction to the best of my abilities

  12. anonymous
    • one year ago
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    Remember, you're plugging the first equation into the second equation once you make the first one c = 20 - h

  13. anonymous
    • one year ago
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    and because you have the variable c in the second equation, you just plug 20- h in as c, and therefore you only have to solve for one variable instead of two making things much easier

  14. anonymous
    • one year ago
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    x+y=20 2x+5=25 then x=5 y=15

  15. anonymous
    • one year ago
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    So first thing, always use the given variables, don't change them or you have a lot bigger chance of becoming confused

  16. anonymous
    • one year ago
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    try again with that in mind

  17. anonymous
    • one year ago
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    ok

  18. anonymous
    • one year ago
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    now im confused:(

  19. anonymous
    • one year ago
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    do i subtract 1 from 2 ?

  20. anonymous
    • one year ago
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    I'm sorry, I got distracted. Alright I will show you how to do it step-by-step

  21. anonymous
    • one year ago
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    im now in a rush

  22. anonymous
    • one year ago
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    :'(

  23. anonymous
    • one year ago
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    c + h = 20 c + 2h = 25 That is our system of equations, now we solve for one variable, then use that value to solve for the other variable: c + h = 20 --> c = 20 - h Using this, we plug it into the second equation: (20 - h) + 2h = 25 --> h = 5 h = 5 back into the first equation, c + 5 = 20, c = 15

  24. anonymous
    • one year ago
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    If you need me to rewrite everything for you to answer the questions more easily tell me

  25. anonymous
    • one year ago
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    thanks so much!!!

  26. anonymous
    • one year ago
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    No problem :) If you have more questions to answer just paste them in here quickly, and I will answer them

  27. anonymous
    • one year ago
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    your awesome!!

  28. anonymous
    • one year ago
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    Well thank you :D

  29. anonymous
    • one year ago
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    So whenever you're ready

  30. anonymous
    • one year ago
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    how old are you?

  31. anonymous
    • one year ago
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    i dont have anymore, all done(:

  32. anonymous
    • one year ago
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    I am 16, and you?

  33. anonymous
    • one year ago
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    15

  34. anonymous
    • one year ago
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    same! what part

  35. anonymous
    • one year ago
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    i am but im doing a "refresher course"

  36. anonymous
    • one year ago
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    I have to do my own final 4 tests for the second segment of Algebra II Honors however, anytime at all, just ask me and I will respond as fast as I can :)

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