anonymous
  • anonymous
Mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $25 to buy a total of 20 packets of wafers of the two varieties. Part A: Write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that Mike and his friends bought at the carnival. Define the variables used in the equations. Part B: How many packets of chocolate wafers and cheese wafers did they buy?Explain how you got the answer and why you selected a particular me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Alright so system of eqations: Lets call the amount of chocolate wafer packets (c) and the amount of cheese wafer packets (h) They bought a total of 20 packets so: c + h = 20 They spent $25 dollars, and chocolate packets were $1 while cheese were $2, so: c(1) + h(2) = 25
anonymous
  • anonymous
Do you get it so far?
anonymous
  • anonymous
yes!

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anonymous
  • anonymous
Alright awesome :) next part, to solve for this, we just use substitution
anonymous
  • anonymous
alright
anonymous
  • anonymous
I think you should try this one out yourself before I give you any answers :P Hint: Solve for h first by making the first equation into c = bla bla bla
anonymous
  • anonymous
5
anonymous
  • anonymous
Do you want to show me your steps and how you got there or are you in a bit of a rush to get something done?
anonymous
  • anonymous
or 15?...-_-
anonymous
  • anonymous
no rush
anonymous
  • anonymous
Alright, so show me step by step what you did and I will guide you in the right direction to the best of my abilities
anonymous
  • anonymous
Remember, you're plugging the first equation into the second equation once you make the first one c = 20 - h
anonymous
  • anonymous
and because you have the variable c in the second equation, you just plug 20- h in as c, and therefore you only have to solve for one variable instead of two making things much easier
anonymous
  • anonymous
x+y=20 2x+5=25 then x=5 y=15
anonymous
  • anonymous
So first thing, always use the given variables, don't change them or you have a lot bigger chance of becoming confused
anonymous
  • anonymous
try again with that in mind
anonymous
  • anonymous
ok
anonymous
  • anonymous
now im confused:(
anonymous
  • anonymous
do i subtract 1 from 2 ?
anonymous
  • anonymous
I'm sorry, I got distracted. Alright I will show you how to do it step-by-step
anonymous
  • anonymous
im now in a rush
anonymous
  • anonymous
:'(
anonymous
  • anonymous
c + h = 20 c + 2h = 25 That is our system of equations, now we solve for one variable, then use that value to solve for the other variable: c + h = 20 --> c = 20 - h Using this, we plug it into the second equation: (20 - h) + 2h = 25 --> h = 5 h = 5 back into the first equation, c + 5 = 20, c = 15
anonymous
  • anonymous
If you need me to rewrite everything for you to answer the questions more easily tell me
anonymous
  • anonymous
thanks so much!!!
anonymous
  • anonymous
No problem :) If you have more questions to answer just paste them in here quickly, and I will answer them
anonymous
  • anonymous
your awesome!!
anonymous
  • anonymous
Well thank you :D
anonymous
  • anonymous
So whenever you're ready
anonymous
  • anonymous
how old are you?
anonymous
  • anonymous
i dont have anymore, all done(:
anonymous
  • anonymous
I am 16, and you?
anonymous
  • anonymous
15
anonymous
  • anonymous
same! what part
anonymous
  • anonymous
i am but im doing a "refresher course"
anonymous
  • anonymous
I have to do my own final 4 tests for the second segment of Algebra II Honors however, anytime at all, just ask me and I will respond as fast as I can :)

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