Jravenv
  • Jravenv
Would you kindly help me? Best answer will be rewarded, Screenshot of the question in the comments.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Jravenv
  • Jravenv
nikato
  • nikato
have you tried it?
nikato
  • nikato
i'll start by finding the common denominator

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Jravenv
  • Jravenv
5 right?
nikato
  • nikato
not quite. you dont add them. you want to multiply them, so 6
nikato
  • nikato
|dw:1434059010282:dw| so we want to multiply each so that their denominator is 6
nikato
  • nikato
|dw:1434059077199:dw| you can do this because its the same thing as multiplying by 1. next, you want to multiply everything out
nikato
  • nikato
|dw:1434059141223:dw| i multiplied it all out and then combined the two since they both have the same denominator
Jravenv
  • Jravenv
so its 1x+6/6 >1?
nikato
  • nikato
|dw:1434059374267:dw| oops. my mistake, should be a 3. and close, its -x. 2-3=-1
nikato
  • nikato
so (-x+3)/6>1 next, you want to multiply both sides by 6
Jravenv
  • Jravenv
so (-x+3)>6 ?
nikato
  • nikato
yes. now subtract 3 on both sides
Jravenv
  • Jravenv
-x>3 ?
nikato
  • nikato
now multiply both sides by -1. remember to switch your sign. and that would be your answer
Jravenv
  • Jravenv
x<-3?
nikato
  • nikato
yup
Jravenv
  • Jravenv
WOOOHOOO

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