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Jravenv

  • one year ago

Would you kindly help me? Best answer will be rewarded, Screenshot of the question in the comments.

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  1. Jravenv
    • one year ago
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  2. nikato
    • one year ago
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    have you tried it?

  3. nikato
    • one year ago
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    i'll start by finding the common denominator

  4. Jravenv
    • one year ago
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    5 right?

  5. nikato
    • one year ago
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    not quite. you dont add them. you want to multiply them, so 6

  6. nikato
    • one year ago
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    |dw:1434059010282:dw| so we want to multiply each so that their denominator is 6

  7. nikato
    • one year ago
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    |dw:1434059077199:dw| you can do this because its the same thing as multiplying by 1. next, you want to multiply everything out

  8. nikato
    • one year ago
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    |dw:1434059141223:dw| i multiplied it all out and then combined the two since they both have the same denominator

  9. Jravenv
    • one year ago
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    so its 1x+6/6 >1?

  10. nikato
    • one year ago
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    |dw:1434059374267:dw| oops. my mistake, should be a 3. and close, its -x. 2-3=-1

  11. nikato
    • one year ago
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    so (-x+3)/6>1 next, you want to multiply both sides by 6

  12. Jravenv
    • one year ago
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    so (-x+3)>6 ?

  13. nikato
    • one year ago
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    yes. now subtract 3 on both sides

  14. Jravenv
    • one year ago
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    -x>3 ?

  15. nikato
    • one year ago
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    now multiply both sides by -1. remember to switch your sign. and that would be your answer

  16. Jravenv
    • one year ago
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    x<-3?

  17. nikato
    • one year ago
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    yup

  18. Jravenv
    • one year ago
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    WOOOHOOO

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