anonymous
  • anonymous
The function f(t) = 30 sin (pi over 3t) −15 models the temperature of a periodic chemical reaction where t represents time in hours. What are the maximum and minimum temperatures of the reaction, and how long does the entire cycle take?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Maximum: 30°; minimum: 15°; period: pi over 3 hours Maximum: 30°; minimum: −15°; period: pi over 3 hours Maximum: 45°; minimum: 15°; period: 6 hours Maximum: 15°; minimum: −45°; period: 6 hours
anonymous
  • anonymous
B
anonymous
  • anonymous
Wait

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anonymous
  • anonymous
i totally don't get this if you can help omg ill give you fans and medals and everything lol
anonymous
  • anonymous
@Hero
Hero
  • Hero
Hi, Brooke, would you at least know the limits of the range of the sine function?
Hero
  • Hero
Do you know the minimum and maximum values of sin(x)?
anonymous
  • anonymous
no, I'm so so so confused. i am taking a test and this is the last question and I'm hopeless and this point
anonymous
  • anonymous
@ashthecutie so would you say B
anonymous
  • anonymous
No let me see
Hero
  • Hero
@brookefahey The minimum value of sin(x) is -1. The maximum value of sin(x) is 1.
anonymous
  • anonymous
okay thats what i thought @Hero thanks for explaining that
Hero
  • Hero
Do you know what to do now that you know this information?
anonymous
  • anonymous
@Hero can you help me with my question
anonymous
  • anonymous
@Hero would i plug in -1 and 1 for sin
Hero
  • Hero
Replace sin(pi over 3t) with -1, then solve for f(t) to find the minimum. Replace sin(pi over 3t) with 1, then solve for f(t) to find the maximum.
Hero
  • Hero
Min of f(t) = 30(-1) - 15 Max of f(t) = 30(1) - 15
anonymous
  • anonymous
that totally makes sense now… so the answer would be D! @Hero
anonymous
  • anonymous
i know you can't give answers but just give me reassurance that i have somewhat of an idea of what is going on
Hero
  • Hero
D is correct.
anonymous
  • anonymous
you are truly the best! thank you sooooo much!

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